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DrChinese
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RUTA said:Bob is moving at v = 1/10 relative to Alice and his worldline passes through (1,10), so it also passes through (0,0). We're using Alice's coordinates so she is always at x = 0. [Note: Bob's worldline passes through (0,0), not the relevant sfc of simultaneity.] A hypersfc of simultaneity for Bob passing through (1,10) has slope 1/10 so it passes through (0,9.9), which precedes (1,10) by t = 0.1 in Alice's frame. Bob sends a signal (ONE) to Alice along this sfc of simultaneity, so Alice receives ONE at t = 9.9 and sends a signal (ZERO) to Bob alg a t = 9.9 sfc of simultaneity in her frame (slope of 0). This sfc of simultaneity intersects Bob's worldline before he sent his ONE at t = 10. The exact values of time for Bob don't matter and the signal itself (ONE or ZERO) that he sends doesn't matter. Whatever Bob sends at t = 10 is inverted at t = 9.9 and returned to him in his past (t = 9.9), so he can't possibly send the same thing he receives. Thanks for the explanation, Fredrik!
I'm sorry I am so dumb, but I just don't follow.
Alice's clock is always moving forward and Bob's clock is always moving forward. But they may not be moving forward at the same rate. Instantaneous Communication (IC) implies that there could be another party, let's say Chris. Chris sends out the time to Alice and Bob via IC. Regardless of their frame relative to Chris, they will always receive timestamps that are moving forward, even if they are different than their own. They will at least agree that at any point, they can see the delta between their own time clock and Chris'.
Now, how does the hypersurface of either Alice or Bob matter? A relativistic hypersurface won't come into play because all communication is by IC. You have a preferred frame because of Chris I guess, how does a causal loop problem appear?
According to Chris's clock (which both Alice and Bob are aware of) which is initially sync'd to both Alice and Bob:
a. Alice at t=0 (per her and Chris' clock) sends a 1.
b. Bob receives a 1 at t=0 (per his and Chris' clock).
c. Bob sends a 0 after some very short delay, let's say it reads t=1 per Chris' clock but t=2 per Bob's clock.
d. Alice receives a 0 at t=1 per Chris' clock but it is t=20 per her clock.
e. Alice sends at 0 to Bob at t=2 per Chris' clock but it is t=21 per her clock.
f. Bob receives a 0 at t=2 per Chris' clock but it is t=2.1 per Bob's clock.
So I guess it seems to me that everyone's clocks are advancing. Of course I do not believe that IC is possible. I am simply saying that IF there were such, how does the paradox arise? I know I should probably understand this, but I don't. HELP!