Does Light Reflect at the Boundary Between Water and Flint Glass?

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At the boundary between water and flint glass, light does indeed reflect as well as refract. Snell's law can be used to determine the angle of refraction, but it does not provide definitive information about reflection without further calculations. Reflection occurs at the interface, even if the amount varies based on the angles and indices of refraction. It is noted that using polarized light can lead to scenarios where refraction occurs without reflection. Overall, both reflection and refraction are present at the boundary, confirming the complexity of light behavior at different mediums.
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Homework Statement



At the boundary between water (n=1.33) and flint glass (n=1.66), incoming light at ~49 degrees from the normal is refracted.

Of course, I can use Snell's law to calculate the angle of refraction.

However, my question is whether any of the light at this boundary is also Reflected??

I think it would be because light reflects off both rough (diffuse reflection) and smooth surfaces, but can anybody confirm?

Thanks!

Homework Equations



N/A

The Attempt at a Solution



See above.
 
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I can confirm that your heuristic reasoning is incorrect. You do not know if it reflects or not unless you run through the equations.

Eyeballing the numbers there is a 50-50 chance you have no refelection.
 
Yes in general reflection and refraction always occur in pairs much as in a transverse wave traveling on a string which is rare on its initial part and denser on the other .You get two waves when the transverse wave approaches the joint one which returns back(reflection) and the other which continues its path (refraction).Mathematically there is a reflection unless the strings are the same .(it is just an analogy).
However using polarized light one can get a refraction with no reflection at all.
Using Snell's law one can only verify whether light can be refracted or not ,if it can then what the angle is.Since the light approaches through the rarer medium (water) there is no scope of total internal reflection which is in a way a synonym for no refraction.
Correct me if I am wrong.
regards
Yukoel
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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