Electric Charges Homework: Find Where Electric Field & Potential Equal 0

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The discussion revolves around determining where the electric field and electric potential are equal to zero between a +10 mC charge and a -2.0 mC charge, placed 0.20 m apart. The initial confusion stems from the assumption that the electric field could only be zero between the two charges, but it is clarified that the field can also be zero outside the charges. The correct position for the electric field to be zero is found to be 0.16 m past the negative charge, while the electric potential is calculated to be zero at 0.05 m from the positive charge. Participants emphasize the importance of understanding the direction of forces and the configuration of the charges when solving these problems. The discussion concludes with a focus on applying the correct formulas to find the positions accurately.
Fusilli_Jerry89
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Homework Statement


A +10mC charge is placed 0.20 m from a -2.0mC charge. Where on the line joining the 2 charges is the a) electric field equal to zero? b) electric potential equal to zero?


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The Attempt at a Solution


I am not sure, but I think that the answer to both of these questions is zero (because infinite is not an option). Am I wrong when I say that the electric field can't be zero because there are two forces pulling in the same direction, therefore they cannot cancel each other out when between them. Also, the electric potential can't seem to equal zero because again, the forces are adding. I'm not as sure about that one though.
 
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Part a first: The field will be zero at a position where you could place a test charge (small positive charge) and it will experience no net force. First decide on the configuration of the "source" charges- i.e. is the +10 m C to the left of the other charge? Then figure out where the field must be zero, conceptually, i.e. to the left of them, between them, or to the right.
 
It seems you are only considering the part of the line between the two charges. Yes, inside the 2 charges, the fields will never equal 0, they will always add, but outside the 2 charges the fields point in opposite directions.

HINT: What is the formula for an electric field? Write down an equation describing the conditions you want. After you do that, solve for the position along the line. The follow the same procedure for the potential.

See how far you can get now. Good Luck!
 
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oh ok, I thought the question meant only between the 2 charges. For the electric field, I got 0.16 m past the negative charge. For the electric potential, I got 0.05m?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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