Electric Feld Intensity Question

In summary, the problem involves finding the electric field intensity vector at point P (5,6) due to an electric charge distribution along an infinite line (2x+3y=7) with a density of 3uC/m. The equation used is E = Integral of pl/ (4*pi*E) * (R - R')/ (R-R')^3, where R and R' are the distances from the point to the x and y intercepts respectively. By finding the distance between point P and the line at the point of orthogonal intersection, labeled as r0, the direction of the electric field can be determined to be in the +x, +y direction due to symmetry. The magnitude of the electric field
  • #1
ee3356
1
0

Homework Statement


An electric charge is distributed along an infinite line (2x+3y=7) in xy-plane with density pl = 3uC/m. Find the Efield intensity vector at point P (5,6).

Homework Equations


E = Integral of pl/ (4*pi*E) * (R - R')/ (R-R')^3


The Attempt at a Solution


I just wanted to double check if all i need to do is find the distance of point P from the y-int and x-int and then just use them as R and R' in the above equation
 
Physics news on Phys.org
  • #2
?? Did you mean x-intercept & y-intercept? If so, i think the answer is no.

Anyway - connect P(5,6) to the line at the point where they meet orthogonally. Call this distance r0.

By symmetry, the direction of E is obviously in the direction of this normal in the +x, +y direction.

The magnitude you can get by integrating k*dq/r^2 where r = r0sec(theta), k = 9e9 in SI units and theta is the angle between r0 and an element of charge along the line dq = pl*r*d(theta). Integrate from 0 to pi/2 & double the result.
 

FAQ: Electric Feld Intensity Question

What is electric field intensity?

Electric field intensity is a measure of the strength of an electric field at a specific point in space. It is represented by a vector quantity and is measured in volts per meter (V/m).

How is electric field intensity calculated?

Electric field intensity can be calculated by dividing the force experienced by a test charge placed in an electric field by the magnitude of the test charge. The formula is E = F/q, where E is the electric field intensity, F is the force, and q is the test charge.

What factors affect electric field intensity?

Electric field intensity is affected by the distance from the source charge, the magnitude and sign of the source charge, and the medium in which the electric field exists. It is also affected by the presence of other charges in the surrounding area.

How is electric field intensity related to electric potential?

Electric field intensity and electric potential are related through the equation E = -dV/dx, where E is the electric field intensity, V is the electric potential, and x is the distance in the direction of the electric field. This means that the electric field intensity is the negative gradient of the electric potential.

What are some real-world applications of electric field intensity?

Electric field intensity is used in a variety of applications, including in capacitors, motors, and generators. It is also used in medical equipment such as MRI machines and defibrillators. Electric field intensity is also important in understanding the behavior of lightning and the Earth's magnetic field.

Similar threads

Back
Top