Electric Field as a function of r, evaluating bounds

AI Thread Summary
The discussion centers on understanding the evaluation of the electric field as a function of distance (r) from a charge distribution. Participants clarify that the enclosed charge (Qenc) is zero only at r=0 and increases until r=R, where it remains constant beyond that point. The original poster expresses confusion about integrating the charge density and determining the limits for Qenc. Ultimately, the key takeaway is that while the electric field behaves differently at various distances, Qenc remains constant for r greater than R. This clarification helps resolve the initial misunderstanding regarding the problem's wording.
guyvsdcsniper
Messages
264
Reaction score
37
Homework Statement
A sphere with radius R has a volume charge density
ρ = ρ0 𝑟⁄𝑅, where ρ0 is constant.

Find the electric field as a function of r, from r=0 to infinity.
Relevant Equations
Eda=qenc/epsilon
Im having trouble understanding the wording to this problem. When it says "from r=0 to r=infinity". My Qenc would zero out. I guess it makes sense that from infinitely far away you wouldn't "feel' the electric field but considering this question leads to 4 other questions I don't think I am approaching this right.

Can anyone help me understand this a little better?
IMG_8416.JPG
 
Physics news on Phys.org
quittingthecult said:
My Qenc would zero out

What do you mean with that ?
##Q_{\rm enc}## is zero for ##r=0## only. It increases with ##r## until ##r=R## and then it stays the same -- all the way.
 
BvU said:
What do you mean with that ?
##Q_{\rm enc}## is zero for ##r=0## only. It increases with ##r## until ##r=R## and then it stays the same -- all the way.
I was referring to integrating the r on the last step of my work.

But i think i understand what the question is really asking based off what you said. I am basically evaluating the electric field at r=0, r=R ? Past R the electric field is constant.

But what would my limits be for the r component of Qenc?
 
quittingthecult said:
I was referring to integrating the r on the last step of my work.

But i think i understand what the question is really asking based off what you said. I am basically evaluating the electric field at r=0, r=R ? Past R the electric field is constant.

But what would my limits be for the r component of Qenc?
The electric field is not constant for r > R, rather ##Q_\text{Enc} ## is constant for r > R .

You need to integrate the charge density to find the charge enclosed within a sphere of radius r, where
0 < r ≤ R .
 
Sorry, I think the wording just completely threw me off. I understand what the questions is asking now. I just confused myself really bad.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Back
Top