Electric Field Calculations for Stationary Charges and a Dipole at Point P(0,4m)

In summary, the conversation discusses finding the electric field vector at a given point and the torque and potential energy of a dipole in an electric field. The solution involves calculating the electric field at two points and determining the direction of the field using the components of the vector. The conversation also raises questions about the use of significant figures and the construction of a right triangle to find the angle of the electric field vector.
  • #1
BHH
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0

Homework Statement


The picture below shows two stationary charges q1= +2mC and q2= -15 mC.
and I need to find the electric field vector at field point P(0,4m). E= [px, py] .

Also
A little dipole is positions in P(0,4m) and is given with p= [px,py]=[2*10^-8 ,0] Cm.

Find the torque that acts on the dipole because of the electric field and its potential energy

Homework Equations


E=k*q/r^2

The Attempt at a Solution


I have found out that E1=4.5*10[6][/SUP] and E2= 1.7*10^6. I am not sure if the electric field E1 is negative or positive ? I think its negative because the vector goes downwards. And when I find the angle for E2 do I use arctan(8/2)?
 

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  • #2
WELCOME TO PF.
BHH said:
I have found out that E1=4.5*10[6][/SUP] and E2= 1.7*10^6.
OK. But I would keep an extra significant figure while doing the calculations. Then round off to the appropriate number of significant figures at the end. Also, don't forget the units.
I am not sure if the electric field E1 is negative or positive ? I think its negative because the vector goes downwards.
Electric field is a vector quantity. It is not good language to say that a vector is negative. However, the components of a vector can be negative or positive. So, if the field points downward (along the negative y axis) then you would say that the y component of the electric field is negative.

And when I find the angle for E2 do I use arctan(8/2)?
This does not look right. Are you trying to find the angle that E2 makes to the horizontal direction or the vertical direction? If you are constructing a right triangle to help find the angle, make sure you have the dimensions of the sides of the triangle correct.
 

FAQ: Electric Field Calculations for Stationary Charges and a Dipole at Point P(0,4m)

1. What is an electric field?

An electric field is a region in space surrounding an electrically charged object, where other charged objects will experience a force when placed in the field.

2. How is the strength of an electric field measured?

The strength of an electric field is measured by the force it exerts on a unit charge placed in the field. This is known as the electric field strength and is measured in newtons per coulomb (N/C).

3. How can I calculate the electric field at a specific point?

To calculate the electric field at a specific point, you can use the equation E = kQ/r^2, where E is the electric field strength, k is the Coulomb's constant, Q is the charge of the object creating the field, and r is the distance from the object to the point where you want to calculate the field.

4. What are the units of electric field?

The units of electric field are newtons per coulomb (N/C) in the SI system and volts per meter (V/m) in the CGS system.

5. How can I visualize an electric field?

An electric field can be visualized by using electric field lines, which show the direction and strength of the field at different points. The lines point in the direction of the field and are closer together where the field is stronger.

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