Elephant Seal's Displacement: 635m Down, 590m East

  • Thread starter Thread starter shawonna23
  • Start date Start date
  • Tags Tags
    Homework
Click For Summary
The elephant seal's displacement can be calculated using the Pythagorean theorem, where the depth of 635 m and the eastward distance of 590 m form a right triangle. By applying the theorem, the magnitude of the displacement is determined to be approximately 866.68 m. The calculation involves finding the hypotenuse, which combines the squares of both sides. This method effectively illustrates how to solve for displacement in a two-dimensional context. The final result confirms the seal's total displacement as 866.68 m.
shawonna23
Messages
146
Reaction score
0
Homework Problem-Help??

In diving to a depth of 635 m, an elephant seal also moves 590 m due east of his starting point. What is the magnitude of the seal's displacement?
 
Physics news on Phys.org
Think Pythagoras! :-)

BTW - what have you done so far on the problem?
 


To find the magnitude of the seal's displacement, we can use the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.

In this scenario, the displacement of the seal can be represented by a right triangle, with the depth (635 m) as one side and the horizontal distance (590 m) as the other side. So, the magnitude of the displacement can be found by calculating the hypotenuse of this triangle.

Using the Pythagorean theorem, we get:

Magnitude of displacement = √(635^2 + 590^2)
= √(403225 + 348100)
= √751325
= 866.68 m

Therefore, the magnitude of the seal's displacement is approximately 866.68 m.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 38 ·
2
Replies
38
Views
8K
Replies
3
Views
3K
Replies
17
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 13 ·
Replies
13
Views
7K
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
4K