Equivalent stiffness and damping

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The discussion centers on calculating equivalent stiffness and damping for a system of springs and dampers. The user initially interprets k1 and k2 as being in parallel, with k3 in series, while dampers c1 and c2 are seen as being in series. However, the textbook suggests that k3 is actually in parallel with k1 and k2, leading to a straightforward summation of their values. The response emphasizes returning to fundamental principles, like Newton's laws, to clarify the forces acting on the mass and validate the textbook's approach. Ultimately, the consensus supports the textbook's explanation regarding the configuration of the springs.
Hood
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Homework Statement


A scheme of springs and dampers is given. What is equivalent stiffness and damping?

vibrations.png


Homework Equations


For stiffness in series: keq=ka*kb/(ka+kb)
For stiffness in parallel: keq=ka+kb
For dampers similarly.

The Attempt at a Solution



To me it looks like k1 and k2 are in parallel. After summation I'd say that k3 is in series and calculate for that. Dampers c1 and c2 seem to be in series so I'd calculate them similarly.

I'm puzzled because textbook says that k3 is parallel to k1 and k2 and simply sums it up (keq=k1+k2+k3). I doubt it's like that, could you also explain about c1 and c2?
 
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Hood said:

Homework Statement


A scheme of springs and dampers is given. What is equivalent stiffness and damping?

vibrations.png


Homework Equations


For stiffness in series: keq=ka*kb/(ka+kb)
For stiffness in parallel: keq=ka+kb
For dampers similarly.

The Attempt at a Solution



To me it looks like k1 and k2 are in parallel. After summation I'd say that k3 is in series and calculate for that. Dampers c1 and c2 seem to be in series so I'd calculate them similarly.

I'm puzzled because textbook says that k3 is parallel to k1 and k2 and simply sums it up (keq=k1+k2+k3). I doubt it's like that, could you also explain about c1 and c2?

Best thing to do is go back to Newton: mx'' = ƩFx.

Call x = 0 when the mass is in its equilibrium position. If m goes up (x > 0) what are the forces acting on m?

You will see that your textbook is right ...
 

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