Figuring out time when you have acceleration and distance.

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To determine the time it takes for a car to travel 30.0 meters with an acceleration of 2.00 m/s², it is assumed that the car starts from rest (initial velocity vi = 0 m/s). The relevant formula for distance under constant acceleration is d = 1/2 at². Rearranging this to solve for time t results in t = √(2d/a). Substituting the values gives t = √(2 * 30.0 m / 2.00 m/s²), leading to the final calculation of time.
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How long does it take a car to travel 30.0m if it accelerates at a rate of 2.00m/s^2?
Given
Distance- 30.0m
A-2.00m/s^2

Do I need to find vi?
 
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You must need to assume it is initially at rest, otherwise the problem is incomplete.
 
1MileCrash said:
You must need to assume it is initially at rest, otherwise the problem is incomplete.

So now I have
Distance- 30.0m
a-2.00m/s^2
vi-0m/s
So can i now use the d=1/2at^2 formula?
But we're solving for t
making the equation t, taking the square root of 2d/a right?
 
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