MHB Find Power Series Representation for $g$: Interval of Convergence

karush
Gold Member
MHB
Messages
3,240
Reaction score
5
$\textrm{a. find the power series representation for $g$ centered at 0 by differentiation}\\$
$\textrm{ or Integrating the power series for $f$ perhaps more than once}$
\begin{align*}\displaystyle
f(x)&=\frac{1}{1-3x} \\
&=\sum_{k=1}^{\infty}
\end{align*}
$\textsf{b. Give interval of convergence of the new series } $

just reviewing but ? on this one
 
Physics news on Phys.org
How are the the functions $f$ and $g$ related?
 
skeeter said:
How are the the functions $f$ and $g$ related?
do you suggest this:
$$\frac{1}{1-x}=\sum_{n=0}^{\infty}x^n$$
 
karush said:
do you suggest this:
$$\frac{1}{1-x}=\sum_{n=0}^{\infty}x^n$$

The information regarding how $f$ and $g$ are related is missing...without that, we cannot help. :D
 
karush said:
do you suggest this:
$$\frac{1}{1-x}=\sum_{n=0}^{\infty}x^n$$

I didn't suggest anything ... I don't know the relationship between $f$ and $g$ because you have not provided that essential piece of information.
 
it was from math lab which I don't have acess to anymore. so g probably was noted there..

sorry I just drop the problem
 
For original Zeta function, ζ(s)=1+1/2^s+1/3^s+1/4^s+... =1+e^(-slog2)+e^(-slog3)+e^(-slog4)+... , Re(s)>1 Riemann extended the Zeta function to the region where s≠1 using analytical extension. New Zeta function is in the form of contour integration, which appears simple but is actually more inconvenient to analyze than the original Zeta function. The original Zeta function already contains all the information about the distribution of prime numbers. So we only handle with original Zeta...

Similar threads

Replies
3
Views
3K
Replies
3
Views
2K
Replies
1
Views
2K
Replies
7
Views
2K
Replies
3
Views
2K
Replies
4
Views
2K
Back
Top