Find the speed with which the box hits the ground.

In summary, the problem involves a box of mass 4kg being lifted to a height of 2m with a constant force F, and then being released with an upward velocity of 5m/s. The magnitude of the force F is found to be 65N. To find the final velocity when the box hits the ground, the equation 0=½mv^2-mgh_i is used, with m=4kg, g=10m/s^2, and h_i=2m. This results in a final velocity of 8.09 m/s.
  • #1
foreverlost
7
0

Homework Statement


A box whose mass is 4kg is at rest on the floor. It is then lifted to a height of 2m by a constant a constant force F and then released. At this point the box has upward velocity of 5m/s. Do not use Newton's laws of motion to solve this problem.

A. Find magnitude of the force F
F=65N

B. Find the speed with which the box hits the ground.
?

Homework Equations


g = 10m/s^2


The Attempt at a Solution



A. Wother = ΔKE + ΔPE = 65N magnitude of force

B. 0 = 1/2mvf^2-1/2m(0)^2 + mg(0) - mghi
= 1/2mvf^2 - mghi
vf = √[(2*mghi)/m] = √2*4*10*2/4 = 6.32 m/s (WRONG)

The speed is supposed to be = 8.09 m/s
I just killed the constant force in the work and substituted in the values as if the box fell to ground. I don't know what I'm missing.

I will return soon.
 
Physics news on Phys.org
  • #2
foreverlost said:
B. 0 = 1/2mvf^2-1/2m(0)^2 + mg(0) - mghi

Why zero here?
 
Last edited:
  • #3
TSny said:
Why zero here?

I assumed it had to be zero for either final or initial velocity. so i can solve for v. i first tried vf = 0m/s to say the object has landed, and then i'd solve for vi with this formula.
 
  • #4
foreverlost said:
1. The problem statement, all variables and given/known

The Attempt at a Solution



A. Wother = ΔKE + ΔPE = 65N magnitude of force

B. 0 = 1/2mvf^2-1/2m(0)^2 + mg(0) - mghi
= 1/2mvf^2 - mghi
vf = √[(2*mghi)/m] = √2*4*10*2/4 = 6.32 m/s (WRONG)

The speed is supposed to be = 8.09 m/s
I just killed the constant force in the work and substituted in the values as if the box fell to ground. I don't know what I'm missing.

I will return soon.

When you solve for v...
0=½mv^2-mgh_i
½mv^2=mgh_i |:m |*2
v^2=2gh_i
v=√(2gh_i)
 
  • #5
foreverlost said:
I assumed it had to be zero for either final or initial velocity. so i can solve for v. i first tried vf = 0m/s to say the object has landed, and then i'd solve for vi with this formula.

Why does one velocity have to be zero? You were given an initial velocity (vi=+5m/s), and you are told to find a final velocity (vf). By your logic, vf must be zero. This makes no sense for two reasons:
1. The ball is accelerating downwards, so as long as it starts from any height above the ground, it should have nonzero velocity when it hits the ground.
2. If you are told to find something, it is very rarely zero.
 

FAQ: Find the speed with which the box hits the ground.

What is the formula for finding the speed of an object?

The formula for finding an object's speed is speed = distance/time.

How do you calculate the distance an object falls?

The distance an object falls can be calculated using the formula d = 1/2 * g * t^2, where g is the acceleration due to gravity (9.8 m/s^2) and t is the time the object has been falling.

Can you find the speed of an object without knowing the distance it falls?

Yes, it is possible to find the speed of an object without knowing the distance it falls. This can be done by using the formula v = g * t, where v is the final velocity, g is the acceleration due to gravity, and t is the time the object has been falling.

How does air resistance affect the speed of an object?

Air resistance can slow down the speed of an object as it falls. This is because the force of air resistance acts in the opposite direction of the object's motion, causing it to experience a drag force. The greater the surface area of the object, the greater the air resistance and the slower the object will fall.

Is there a limit to how fast an object can fall?

Yes, there is a limit to how fast an object can fall. This is due to air resistance, which increases as the object's speed increases. Eventually, the air resistance will equal the force of gravity, causing the object to reach a terminal velocity and stop accelerating. The terminal velocity varies depending on the object's shape and surface area.

Back
Top