- #1
Helly123
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Homework Statement
Homework Equations
internal change = $$\frac{3}{2}n.R.(T2 - T1)$$
Work = P.ΔV
The Attempt at a Solution
1) T2 = $$\frac {P2. V2 . T1 }{P1 . V1} = 1.2 * 10^3$$
2) Q = Internal change =
$$\frac{3}{2}n.R.(T2 - T1) $$
$$ = \frac{3}{2} * 1 *8.3*10^{-3}*(12*10^2 - 3*10^2) $$
$$ = 112.05 J $$ (the answer is 9*10^2)
3) work BC = the are of triangle ABC = $$9*10^2 $$ (the answer is 1.5*10^3)
4) Heat released is it the same as Heat final - Heat initial ?
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