Find "x" for Pulley Problem of 5kg & 1kg Masses

F = ma to the two masses? :wink:In summary, there are two masses, one of 5kg and one of 1kg, on either sides of a pulley with a vertical and straight string. The heavier mass is doubled and the downward acceleration on the string of the heavier mass is "x". To find "x", we need to use F = ma for both masses, taking into account the tension, T, and the acceleration, a.
  • #1
jk13
3
0


There are two bodies of mass 5kg and 1 kg on either sides of a pulley. (The string stays vertical and straight at all times). The heavier mass is doubled. The downward acceleration on the string of the hevier mass is "x". Find "x" when g=10m/s-2.
Please help fast!
Desperate!
 
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  • #2
welcome to pf!

hi jk13! welcome to pf! :smile:

(try using the X2 button just above the Reply box :wink:)
jk13 said:
There are two bodies of mass 5kg and 1 kg on either sides of a pulley. (The string stays vertical and straight at all times). The heavier mass is doubled. The downward acceleration on the string of the hevier mass is "x". Find "x" when g=10m/s-2.

(what do you mean by "The heavier mass is doubled" ? :confused:)

call the tension "T", and do F = ma twice, once for each mass …

show us what you get :smile:
 
  • #3


The mass 5 kg is doubled. :p
f=ma
f=5*10=50
f=1*10=10
Correct?
 
  • #4


Help me please?! :(
 
  • #5
hi jk13! :smile:
jk13 said:
f=ma
f=5*10=50
f=1*10=10

no, that's weight = mg

you need Ftotal = ma, and you need to include the tension, T, and the acceleration, a
 

FAQ: Find "x" for Pulley Problem of 5kg & 1kg Masses

What is the Pulley Problem of 5kg & 1kg Masses?

The Pulley Problem of 5kg & 1kg Masses is a physics problem that involves calculating the value of "x" in a system consisting of a 5kg mass and a 1kg mass connected by a pulley.

How is "x" related to the Pulley Problem of 5kg & 1kg Masses?

"x" represents the displacement of the 5kg mass in the Pulley Problem. It is the variable that needs to be solved for in order to fully understand the dynamics of the system.

What is the equation for finding "x" in the Pulley Problem of 5kg & 1kg Masses?

The equation for finding "x" is x = (m1/m2) * d, where m1 represents the 1kg mass, m2 represents the 5kg mass, and d represents the distance between the two masses.

What assumptions are made in solving the Pulley Problem of 5kg & 1kg Masses?

Some common assumptions made in solving this problem include assuming the pulley and string are massless, neglecting friction and air resistance, and assuming the system is in equilibrium.

How can the Pulley Problem of 5kg & 1kg Masses be applied in real life?

This type of problem is often used to understand the principles of mechanics and how forces and masses interact in a system. It can also be applied in engineering, such as in designing pulley systems for lifting heavy objects.

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