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rabar789
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[SOLVED] Forces and Motion Midterm Review
A bulldoezer drags a log weighing 500N along a rough surface/ The cable attached to the log makes an angle of 30 degress with the ground. The coefficient of static friction between the log and the ground is 0.500. What minimum tension is required in the cable in order for the log to begin to move?
F=ma
Ffriction = (coefficient of static friction)(Fnormal)
OK after creating a free body diagram I wrote the equations for the sum of the forces in the X and Y dimensions.
FY = Fg (500) + Ftension(sin30) = Fnormal
FX = Ftension(cos30) - Ffriction = ma
Thus, after a lot of substituting and finding the friction, I came out with an answer of 1866.03 Newtons. I don't know what the correct answer should be; I think I'm relatively close, as I received a 15/20 for work, etc. Can someone help me find the answer?
Homework Statement
A bulldoezer drags a log weighing 500N along a rough surface/ The cable attached to the log makes an angle of 30 degress with the ground. The coefficient of static friction between the log and the ground is 0.500. What minimum tension is required in the cable in order for the log to begin to move?
Homework Equations
F=ma
Ffriction = (coefficient of static friction)(Fnormal)
The Attempt at a Solution
OK after creating a free body diagram I wrote the equations for the sum of the forces in the X and Y dimensions.
FY = Fg (500) + Ftension(sin30) = Fnormal
FX = Ftension(cos30) - Ffriction = ma
Thus, after a lot of substituting and finding the friction, I came out with an answer of 1866.03 Newtons. I don't know what the correct answer should be; I think I'm relatively close, as I received a 15/20 for work, etc. Can someone help me find the answer?