HELP Friction on Ice involving weight

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To determine the coefficient of kinetic friction between the tires and the icy road, the acceleration of the car must first be calculated, which is found to be -0.5303 m/s². This value is derived from the equation v = v0 + at, using the stopping distance of 26.4 m. The relationship between acceleration and friction can be expressed as a/g = μ, where g is the acceleration due to gravity. The user expresses confusion about the process and seeks additional resources for equations related to friction. Understanding these concepts is crucial for solving the problem accurately.
imadagron89
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You are driving a 2580.0 kg car at a constant speed of 14.0 m/s along an icy, but straight, level road. As you approach an intersection, the traffic light turns red. You slam on the brakes. Your wheels lock, the tires begin skidding, and the car slides to a halt in a distance of 26.4 m. What is the coefficient of kinetic friction between your tires and the icy road.



The Attempt at a Solution


I found the acceleration to be -.5303 by taking -14/26.4 (v=v0+at) but now I'm confused as how to find the kinetic friction by stopping
 
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Find the acceleration or deceleration, then

a/g = \mu, since Ffriction = ma = \mu W = \mumg.
 
im sorry man still not getting it, is there some sort of website that has all the equations on it?
 

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