HELP ME with THESE QUESTIONS P L E A S E thanks

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In a static equilibrium scenario involving a ladder leaning against a wall, the friction force must act at the ground to prevent slipping. For the pendulum problem, the period of 1.66 seconds and a pendulum length of 1.00 meter can be used to calculate the acceleration due to gravity on the planet. Relevant equations include the formula for the period of a simple pendulum, T = 2π√(L/g), where T is the period, L is the length, and g is the acceleration due to gravity. To find g, rearranging the formula is necessary after substituting the known values. Clear calculations and the correct application of these equations are essential for solving both problems.
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HELP ME with THESE QUESTIONS P L E A S E ! thanks

6) a ladder on the ground is leaning against a wall. if the ladder is in static equilibrium,where must a friction force act on the ladder?
a. at the wall
b. at the ground
c. both

7) the period of a simple pendulum in a grandfather clock on another planet is 1.66s. what is the acceleration due to gravity on this planet? assume the length of the pendulum is 1.00m
 
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