- #1
chrisbroward
- 9
- 1
- Homework Statement
- Find surface charge density required for t = 11.4 ms (11.4 * 10^-3 s)
Answer in μC/m^2
- Relevant Equations
- q = -3.84 mC (-3.84 * 10^-3 C)
m = 3.38 g
ⱴ = 6.81 km/s (6810 m/s)
θ = 69.1°
all at t = 0.
I don't know if i'm exactly right.
But I started with x(time) = V cos θ t
which = (6810 m/s) cos (69.1°) (11.4 * 10^-3 s)
is ... 27.69 m
& since Electric field due to uniformly charge surface is represented by...
E = (q * σ)/(2 * ε_0 * m), and since acceleration (a) can be expressed as F/m, and Force (F) can be express as q*E;
I can combine these two equations...
a must be = (-3.84 * 10^-3 * σ)/(2 * (8.85 * 10^-12) * (3.38 * 10^-3)),
which is -6.418 * 10^10 * σ = a.
But as you can see now I have two unknowns and can't solve :(
Can anyone outline what exactly i'm doing incorrectly?