How can an vehicle move faster than the wind that is powering it?

In summary, the conversation discusses the concept of a wind-powered vehicle, such as an iceboat or sailboat, being able to travel faster than the wind speed that is powering it. It is debated whether this is possible and how it could work. Some suggest that it is a hoax, while others provide explanations based on physics and mechanics. It is also mentioned that iceboats can achieve high speeds by sailing at an angle to the wind, rather than directly downwind. The conversation ends with a discussion about the diagrams in an article about iceboat sailing, and whether they accurately represent the angles and speeds involved.
  • #36
Jeff Reid said:
A bit different than the normal wing case because the "lift" force from the skate is not perpendicular to the apparent wind. This is one source of confusion.

I hope I dealt with that adequately above, but I think it's also worth noting that this is the secret to the whole thing. considering a sailboat, the keel is the wing in the water (fluid A) while the sail is the wing in the air (fluid b). This is the clever way the vessel exploits the energy available at the wind/water interface - while it can only exploit the energy of the wind/sail interface when running straight downwind.

If you consider a bird that is dynamically soaring, he's doing the same thing as the keel and sail, but his wings simply perform both functions, and his momentum is the "structure" that tie the two together so he can exploit the energy that comes from the interface of two airmasses (or more commonly, a wind gradient).
 
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  • #37
schroder said:
Let me see if I understand what is being said here: You place this machine on a treadmill with a backstop so it stays in place. Next, you run the treadmill and let the moving tread do work on the wheels. The wheels then do work to turn a belt, which in turn does work to spin a propeller. Then a velocity is reached where the combination of lift generated by the propeller and feedback to the wheels allows the thing to move forward. Is that what the claim is?

Close, but you're off in a subtle but critical way. There is no feedback to the wheels in the sense that I think you mean. The wheels will alway be a source of drag on the treadmill. However the prop is pushing the car forward by an amount greater than the drag the wheels provide.

The claim is that now the machine is doing work on the treadmill

That would be nice - but no. The treadmill provides all the energy in this case (just as the wind provides the energy in the case of operating on a stationary surface).


I need to get one of those! :smile:


I think I can put you in a nice one that will fit your needs and budget.
 
  • #38
Trond said:
While the discussion about sailing is interesting, most are missing one vital point. The contraption it's referred to isn't powered by wind, but by the wheels, which is clearly described by the builder...
One issue is that propellers operate in their own induced wash, which is significantly different than an ice boat. Helicopters consume more power in a hover than in forward flight for the same reason, while in a hover they operate in their own induced downwash.

spork said:
If you consider a bird that is dynamically soaring.
This is different. Dynamic soaring takes advantage of differing wind speeds separated by a thin shear boundary, by flying through the shear boundary in and out those different regions of wind speed repeatedly. The bird doesn't experience both wind speeds at the same time. A sail craft does experience the difference between wind and ground or water speed at the same time.

Also it turns out that dynamic soaring birds are also getting slope lift from the upwash off the upwind side of waves (which explains why albatrosses routinely climb to 50 feet instead of just 10 feet or so). However dynamic soaring does work as evidenced by radio control gliders. The last time I checked the record was 365mph. There's a youtube video of a 333mph run.

http://www.youtube.com/watch?v=Vi0hrjqU15I&fmt=18

By the way, your diagram attachment still shows as a red x, so apparently it's not been uploaded by physics forums yet. You might want to use an alternate host in the meantime.

On a bit of a side note, one of those sailing sites asked what would happen if a powered fan at the back of a boat directed the air towards a sail which then diverted the air flow backwards. The given answer was that the boat would move in forwards, but this ignores the fact that the fan is accelerating air from behind the fan forwards. What happens between fan and sail doesn't really mater because it's internal to the boat. The boat only moves forwards if the net backwash of air has more momentum change than the net forward wash of air drawn into the fan. This could happen if the pressure jump across the fan disc was high enough, and the sail was efficent enough. Jet engines can reverse thrust, but the pressure jump is huge because of the thermal jump from combustion.
 
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  • #39
spork said:
It's just that in the case of the cart, the sail (prop tips) are on a continuous spiraling downwind tack.

Kinda like any propeller and I know this is your view of the problem spork. For me it's not necessary to repeat it. I still feel you have a way to complicated view of the problem.

You keep talking of L/D ratio for the propeller blades while I prefer Goodmans version where L/D is the ratio between thrust from the propeller and the sum of airdrag, wheeldrag and friction in the system. As long as this value is >1 you are good to go.

Goodman:
The key point is that the propeller is a propeller, not a wind vane

Which means you are not sailing.

And btw, the heading:
How can an vehicle move faster than the wind that is powering it
is not the problem of the cart. The ice yacht yes, but not the cart, as it's powered by the rolling wheels and not the wind, as per Goodman who is one of those that have built one.
 
  • #40
Jeff Reid said:
This is different. Dynamic soaring takes advantage of differing wind speeds separated by a thin shear boundary, by flying through the shear boundary in and out those different regions of wind speed repeatedly. The bird doesn't experience both wind speeds at the same time. A sail craft does experience the difference between wind and ground or water speed at the same time.

I agree. That's why I said the bird uses its momentum as the "structure" to allow it to exploit the energy that could be extracted from the differing speed of the two fluids. The boat sticks a wing in both fluids simultaneously, while the bird has to fly back and forth between them to get his wings in one then the other. His momentum is what ties it all together.

Also it turns out that dynamic soaring birds are also getting slope lift from the upwash off the upwind side of waves (which explains why albatrosses routinely climb to 50 feet instead of just 10 feet or so).

True that birds can exploit this second source of energy/lift - but that is not a requirement for dynamic soaring. It's possible for them to stay aloft for hours with no flapping and no vertical wind component. But... that comparison is not central to this situation. I'd love to discuss dynamic soaring too, but I'm eager to see if we can get on the same page with respect to this DWFTTW issue.


By the way, your diagram attachment still shows as a red x, so apparently it's not been uploaded by physics forums yet.

That's bizarre! I didn't realize what you meant initially about the red x. It's working fine in my browser. It's a .gif image. Is it possible that it's a problem with your browser? This is where it's supposed to be:

https://www.physicsforums.com/attachment.php?attachmentid=15991&stc=1&d=1224565850


On a bit of a side note, one of those sailing sites asked what would happen if a powered fan at the back of a boat directed the air towards a sail which then diverted the air flow backwards. The given answer was that the boat would move in forwards, but this ignores the fact that the fan is accelerating air from behind the fan forwards.

Yes. This is the same principle as a thrust reverser on a jet engine (but I'm sure you knew that). One of the guys on another forum actually made a little video where he did exactly that to test my claim that this would happen.
 
  • #41
Trond said:
Which means you are not sailing.

Two points here...

1) Goodman is a very sharp guy, but he's not an aerodynamicist.
2) When he and I have discussed this I got the definite impression that the point he is trying to make is that the transmission is not working in the way that many people assume it is. Clearly the wheels cause the prop to turn, just as the prop causes the cart to move forward - resulting in the wheels turning.

None of this implies that the cart is "not sailing" or is not powered by the wind. I think anyone that saw this vehicle moving downwind faster than the wind on a static road would agree it is being powered by the wind. But as I've said, that's strictly a matter of reference frame. If you're working from the reference frame of the wind you are perfectly justified to call this vehicle "road powered" if you like.

Finally, I know you think my explanation is overly complicated. But I assure you the operation of this cart is aerodynamically identical to the ice-boat on a downwind tack. I understand your desire to simplify it, but your approach simplifies it beyond the point of describing how it can actually work.

...as per Goodman who is one of those that have built one.

Initially, I independently concieved of this design, based entirely on the ice-boat analogy. You just wrap the ice-boat's downwind tack in a spiral and you realize this can be done directly downwind with a prop on a cart. True I was not the first to conceive of such a design. I think Bauer probably gets the credit for that. True Goodman built one - and I haven't. But I don't know whether he conceived of in independently or copied Bauer. Finally, I'm pretty confident that Goodman and I are on the same page since I've discussed this with him many times. Please don't be so sure he would agree with your simplifications. You're reading far too much into his words.
 
  • #42
Jeff Reid said:
By the way, your diagram attachment still shows as a red x, so apparently it's not been uploaded by physics forums yet. You might want to use an alternate host in the meantime.

Here you go:

http://www.putfile.com/pic/8419299
 
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  • #43
Trond said:
While the discussion about sailing is interesting, most are missing one vital point. The contraption it's referred to isn't powered by wind, but by the wheels, which is clearly described by the builder...

Trond:

First, the sailing discussion simply serves as a starting point for DWFTTW (or DDWFTTW). Most people are like Topher -- they absolutely believe that a sailing craft would have to be over-unity to beat the balloon. Once the fallacy of this position can be demonstrated the discussions regarding the cart generally get much more interesting and productive. I'm not saying that everyone then believes the cart works -- far from it ... I'm saying that at least then they can look at the cart without saying "if it goes faster than the wind it's automatically over-unit".

Second, your statement saying the cart "isn't powered by the wind, but by the wheels, which is clearly described by the builder" is absolutely wrong and a misrepresentation/misunderstanding of anything Jack may have said. Jack built the cart *specifically* to prove that a device powered *only* by the wind could go, steady state, directly downwind faster than the wind.

Remember, Jack just built a smaller version of a long existing design (Baur cart) and like all of us, even a builder can fall prey to a use of words that is less than perfect. There is no question the cart is wind powered and no question that the builder knows this.

JB
 
  • #44
How come this thing will advance on a threadmill without any wind present?
 
  • #45
spork said:
Close, but you're off in a subtle but critical way. There is no feedback to the wheels in the sense that I think you mean. The wheels will alway be a source of drag on the treadmill. However the prop is pushing the car forward by an amount greater than the drag the wheels provide.



That would be nice - but no. The treadmill provides all the energy in this case (just as the wind provides the energy in the case of operating on a stationary surface).





I think I can put you in a nice one that will fit your needs and budget.

I see. So the treadmill is exerting a force on the cart which is trying to accelerate it backwards. The restraint prevents this, so the turning wheels transmit force to the prop which then tries to accelerate the cart forward. And, the force of the prop on the cart is greater than the force of the treadmill on the wheels, so it moves forward. So what you are describing is a force multiplier. A simple lever is a force multiplier but the output force cannot be used to drive the input! What you are really describing here is a perpetual motion machine and it is an elaborate hoax. I am surprised that this thread has been allowed to continue for as long as it has.
 
  • #46
Trond said:
How come this thing will advance on a threadmill without any wind present?


To the sail (propellor), there's as much wind present on the treadmill as on the street.

This is only meant in a constructive manner Trond, but the fact that you asked the above question is a perfect demonstration of your lack of understanding of how the cart works.

You insist on attempting to explain it to others and you are critical of Sporks explanations, but in the end you will have little success if you continue to believe you understand something that by your own questions you demonstrate that you do not.

In operation, the spinning sail/propellor sees the *exact* same wind and *exact* same forces on the treadmill as on the street -- the entire cart can't differentiate between the two (frames of reference are like that after all).

JB
 
  • #47
I am surprised that this thread has been allowed to continue for as long as it has.

You and me both, schroder.
 
  • #48
To the sail (propellor), there's as much wind present on the treadmill as on the street.

Please elaborate that. Are you saying that the wind the propeller feels because it's turned by the wheels is making the propeller turn faster?
 
  • #49
schroder said:
...so the turning wheels transmit force to the prop which then tries to accelerate the cart forward.

You've got it half right.

During initial startup, something *does* have to get the sail moving/spinning. On the street, it either the drag of the entire device slowly being 'blown' down with the wind or simple chassis push. On the treadmill, as you point out, it's the restraint 'pushing' the chassis while the wheels spin up the prop.

The half you are missing is that once the sail begins to 'see' apparent wind at the appropriate angle, it generates thrust (just as a sailboat sail does) and it is this thrust that pulls the cart off the treadmill restraint. Again, the gearing between the wheels and the sail/prop only serves to set the tack angle of the sails.

JB
 
  • #50
Also, I have constructed a vector diagram and analyzed it as I have asked spork to do several times. Its pretty clear just by looking at the diagram itself that the thing will never have a downwind component faster than the wind. If I have time today, which I probably wont, I'll graph the resulting equation you get from the graph to make the point a little more clear. I'll get it all posted by the end of the weekend at the latest.
 
  • #51
Topher925 said:
You and me both, schroder.

Topher -- what, you've got no response to the land sailors beating the cr** out of the balloon?

JB
 
  • #52
Trond said:
Please elaborate that. Are you saying that the wind the propeller feels because it's turned by the wheels is making the propeller turn faster?

Trond, I will get back to you soon -- beginning my commute.

JB
 
  • #53
Trond said:
How come this thing will advance on a threadmill without any wind present?

I've said many times now that it doesn't matter whether the road moves or the air moves. This is the whole business of inertial reference frames. Einstein tells us that they're identical. I've explained to you that an airplane and pilot cannot detect any difference between flying upwind and downwind. You really do need to gain an understanding of what an inertial frame is.

schroder said:
What you are really describing here is a perpetual motion machine and it is an elaborate hoax.

Seems like you should accept that $100K bet. Sounds like easy money since even I know a perpetual motion machine is impossible.

Topher925 said:
Also, I have constructed a vector diagram and analyzed it as I have asked spork to do several times.

I guess you haven't seen the diagram I posted on both this and the other forum. I guess you haven't seen my explanation detailing every aspect of the diagram.

Its pretty clear just by looking at the diagram itself that the thing will never have a downwind component faster than the wind.

Either your diagram is wrong, you're interpretting it wrong, or both.

If I have time today, which I probably wont, I'll graph the resulting equation you get from the graph to make the point a little more clear.

Forget the "resulting equation" - show us your diagram.
 
  • #54
ThinAirDesign said:
Topher -- what, you've got no response to the land sailors beating the cr** out of the balloon?

JB

Response to what? All you have done is just made some claim with no real evidence or any type of analysis to support it. What am I suppose to respond to?
 
  • #55
Topher925 said:
Response to what? All you have done is just made some claim with no real evidence or any type of analysis to support it. What am I suppose to respond to?

I imagine he'd like to hear what you have to say to the land sailors that he quoted. The ones who say they actually do this, and that it's easy even for a relatively low performance land yacht.

By the way - you want analysis? I've posted a vector analysis showing exactly why this is possible and how it works. Given that I have an M.S in aero engineering I think that qualifies as "analysis". And I assure you it's absolutely correct.

Personally I find GPS data pretty compelling as well.
 
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  • #56
Topher925 said:
Response to what? All you have done is just made some claim with no real evidence or any type of analysis to support it. What am I suppose to respond to?

Yeah, the President and multiple members of the national sanctioning body for land yacht races stating unanimously that they exceed 1.0 vmg by multiples -- that's "no real evidence".[sarcasm off]

These land sailors providing L/D and other performance data such as:

Vb = Vt * sin(gamma - beta) /sin(beta)
Vb: yacht speed
Vt: true wind speed
gamma: course sailed relative to true wind (gamma = 0 is straight
into the wind)
beta: apparent wind angle, measured between course over the ground
and the apparent wind vector

The closer the yacht can sail to the apparent wind (small beta), the
faster it goes. A typical beta for an efficient landyacht is on the
order of 14 degrees, which yields a maximum boat-speed ratio of 4
times the true wind, and a maximum Vmg downwind of 2.5 times the true
wind.

No analysis there is there.


Look, it's fine to disagree with these guys, but simply saying "there's nothing to respond to" rather than discuss it with me (or better yet, with the guys who do it over on their forum) is just a major copout.

You want to talk about "real evidence" ... How much more *real* does evidence get than guys in wind powered craft with VMGs of over 1.0?

Do you think these guys are lying to us or mistaken when they say that on a 45degree downwind tack and in a 15mph wind, they can achieve 22mph over the ground? This isn't some fuzzy line for them that they may or may not be crossing --- they claim to be achieving multiples of this. Kinda hard to confuse 22mph and 66mph.

So, are they lying? Can they not tell the difference between 22 and 66mph? Are they in on some sinister plot to keep this thread from being dumped to GD? Or perhaps could it be that you have just missed something?

Think about it, and yes ... a thoughful response would be nice. You, the OP asked a question. I managed to dig up some interesting evidence. Seems the perfect place for interaction.

JB
 
  • #57
Trond said:
Please elaborate that. Are you saying that the wind the propeller feels because it's turned by the wheels is making the propeller turn faster?

I'm saying that the wind the propeller feels creates *thrust* -- whether that thrust then makes the propeller turn faster depends on whether the total drag of the device at that moment is less than the generated thrust -- it of course can't spend more than it earns.

JB
 
  • #58
This confusion people have about the wheels "driving" the propeller really would make more sense if they understood the way the gearing is utilized -- exactly the same way that the skates on an ice-boat are utililized.

The skates on an ice-boat constrain the path of the sail to some angle relative to the true wind (say 45 degrees). If you are in the middle of a downwind 45 degree tack (or reach) and suddenly the skates become castors, the path of the sail reverts to straight downwind, relative wind is lost and thus thrust is lost. Soon, the vehicle slows to something less than the speed of the true wind.

The pullies and belts between the prop and the wheels provide the same constraint as the skates to -- they ensure that the sail (prop) moves through the air at the exact same angle as the ice-boat sail. Cut the belt and you get the same result as the castoring skates -- the path of the sail (prop) is no longer 45 degrees, there is no more relative wind and thus thrust is lost. Soon, the vehicle slows to something less than the speed of the true wind.

I know some of us keep saying almost the same thing over and over, but those that resist the sailing comparisons are losing out *precisely because* the cart is nothing more than two sailing devices (ice-boats or land-yachts or sailboat - take your pick) mounted on a chassis. It is only the chassis that is going *directly* downwind, while the two sailing devices continue merrily on their 45 degree, relative wind creating, thrust generating way.

JB
 
  • #59
The half you are missing is that once the sail begins to 'see' apparent wind at the appropriate angle, it generates thrust (just as a sailboat sail does) and it is this thrust that pulls the cart off the treadmill restraint. Again, the gearing between the wheels and the sail/prop only serves to set the tack angle of the sails.

So the propeller turns solely by itself as soon as it starts turning, is that what you are saying? (Y/N?)

Let's keep with the cart on the treadmill here and let's assume it's held back perhaps by a tensiometer, no wind. What's making the propeller spin?
The apparent wind created by it's own rotation, is that what you are claiming? (Y/N)
 
  • #60
If it can go downwind faster than the wind, then it can sail when there is no wind. After all, that would just be going "faster" than the stationary air around it.

In fact, it must do exactly that at some point during the test run in the video. Somewhere along that run, the craft is stationary relative to the air around it, yet contiues to accelerate. This means that, as stated above, the craft can sail during a dead-calm. This amounts to a sailing craft that needs no energy input to provide propulsion.
 
  • #61
In order to understand this you need not understand sailing, relative wind, apparent wind or ANYTHING other than Newtons 1st law.

To get your head around this, imagine the cart facing west sitting on a long treadmill in a long windless hallway. Start the treadmill which runs towards the east and slowly increase the treadmill speed until the cart is at the perfect “break even” point. In other words, to an observer standing still in the hallway, the cart appears to also be standing perfectly still even though it is on the treadmill with its wheels spinning and propeller turning. This is the point where the cart goes EXACTLY as fast as the wind downwind. We don’t need it to go faster than the wind downwind yet. Right here at the break even point is the best place to get your head around it.

Now you don't need to understand anything more that two simple ideas:

1. You must understand Newton’s 1st law of motion - specifically pertaining to balanced and unbalanced forces. In order for the cart to appear to stand perfectly still on the treadmill, the forces pushing on the cart from the east must equal the forces pushing on the cart from the west.

In other words, let’s say that the treadmill is expending 10 Newtons of energy driving the cart east. Since the forces are balanced, the propeller on the cart must be expending 10 Newtons of energy driving the cart west in order to hold it stationary. Since the cart is not experiencing ANY wind pushing it at this point, all its energy driving it west must come from thrust generated by the propeller.

2. You must understand that mankind has yet to invent a machine simple or complex that outputs 100% of the energy it consumes. A propeller is at best 85% efficient. Add in the other components of friction and well it all goes downhill from there. In other words it would be impossible for the cart even get to this break even point. It will never generate thrust equal to the energy it consumes. Now to go even faster than the wind it will have to generate thrust IN EXCESS of the energy it consumes which of course is never going to happen.

Since you now understand these two simple ideas, you can now conclude that the video can only be either:

A. A hoax.
B. Some other "artifact" captured on film.

So here it is reduced to it's minimum components. Nothing to obfuscate here. Very simple.

If you contend that it is possible then all you need to answer is this simple non-obfuscated problem:

Let's suppose that the treadmill imparts a continuous 10 Newtons of force where the treadmill belt strikes the wheels. Please lay out the equations for me assuming your propeller is 90% efficient (that would be an awesome propeller BTW) and there is no friction in the inner gearing of the device. Show me where the device is able to generate continuous thrust in excess of 10 Newtons in order to break even and stand still.

It's a simple equation I assure you. If you need the equation I can point you toward it.

So if you would please lay it out for us where 10N into the propeller results in >= 10N of thrust out.
 
  • #62
I just wanted to address the problem of whether a wind power craft (sailboat or ice-boat etc) could zig-zag downwin faster than the speed of the wind. This I believe might be possible.

Starting only with the assumption that a craft could travel into the relative headwind (apparent wind) at an acute angle phi I calculated the downwind component of the craft velocity and determined when it was a maximum.

Note that this analysis doesn't address the case where the craft is traveling directly downwind because it doesn't properly consider the fact the relative wind speed will appraoch zero.

See attached figure where,

W = wind velocity.
V = craft velocity.
A = relative (or apparent) wind velocity.Applying the sine rule to the velocity magnitudes gives,

[tex]\frac{V}{\sin( \phi + \theta)} = \frac{W}{\sin \phi}[/tex].

BTW. Recall that [itex]\sin( \phi + \theta) = \sin(\pi - \phi - \theta)[/itex]

Rearranging and simplifying gives,

[tex]\frac{V}{W} = \frac{\sin( \phi + \theta)}{\sin \phi} = \cos \theta + \cot \phi \,\, \sin \theta [/tex].

Define alpha as the ratio of downwind velocity component to wind-speed,

[tex]\alpha = \frac{V \cos \theta}{W} = \cos^2 \theta + \frac{1}{2} \, \cot \phi \, \sin(2 \theta)[/tex].

Differentiating wrt theta (and simplifying) gives,

[tex]\frac{d \alpha}{d \theta} = \cot \phi \, \cos(2 \theta) - \sin(2 \theta)[/tex]

Stationary point is at,

[tex]\tan(2 \theta) = \cot \phi [/tex],

[itex]\theta = \pi/4 - \phi/2[/itex]. (assuming phi is acute).

You can show that this corresponds to a maximum. Substituting this back into the expression for alpha gives (after some simplification),

[tex] \alpha_{\max} = \frac{1}{2} \, ( 1 + \cosec \phi )[/tex]

Since cosec(phi) is greater than one it follows that the maximum value of alpha is also greater than one.
 

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  • #63
Sorry but latex seems to be hopelessly messed up today. I think it must be a bug in the forums hopfully they'll get it sorted out soon.
 
  • #64
Trond said:
So the propeller turns solely by itself as soon as it starts turning, is that what you are saying? (Y/N?))

N

Let's keep with the cart on the treadmill here and let's assume it's held back perhaps by a tensiometer, no wind. What's making the propeller spin?

Your question can't be answered as asked as there is a problem with it: If the cart is bing "held back", then the sails (prop) are obviously creating thrust. If there is thrust, then then the propeller is spinning. If the propeller is spinning, then there is wind over the prop. See, your "held back perhaps by a tensionmeter, no wind" is a question that just doesn't make any sense.

All I can do for you at this moment is the following ...

Here's the 'force path':

1: The relative wind powers the tacking sails (spins the prop).

2: The sails (prop) pull the cart forward. If you know the purpose of a "thrust bearing", it would be this bearing on the prop shaft transfering the load from the sails to the cart.

3: The cart's movement relative to the ground spins the wheels, axle and lower pulley.

4: The lower pulley *pulls down* on the belt. (this is key to remember, it's the side of the belt going DOWN that's under tension. If one used two spools of hi-strength line rather than a belt, the line would move from the upper to the lower spool)

5: The upper pulley rotates in response to the belt/line tension, constraining the prop to a fixed tacking angle. The gearing ratio between the wheels, these pulleys and the prop pitch determine the angle of the sail tack.

(Notice in the above, I didn't say "powering the prop", I said "constraining the prop" -- the line merely provides a 'keel or skate constraint', and there's a BIG difference between "constrain" and "power" -- it only takes a small force (less than the thrust bearing is absorbing) to provide the constraint. If the belt/line were *powering* the prop, we'd have a perpetual motion device on our hands, and we all know how those work out)

The apparent wind created by it's own rotation, is that what you are claiming? (Y/N)

See above.

JB
 
  • #65
LURCH said:
If it can go downwind faster than the wind, then it can sail when there is no wind. After all, that would just be going "faster" than the stationary air around it.

In fact, it must do exactly that at some point during the test run in the video. Somewhere along that run, the craft is stationary relative to the air around it, yet contiues to accelerate. This means that, as stated above, the craft can sail during a dead-calm. This amounts to a sailing craft that needs no energy input to provide propulsion.
this is not true. You are dropping a piece of the puzzle.

The craft [in motion wrt ground but with no relative wind] is NOT the same as the craft [stationary wrt ground but with no relative wind]. They are not equivalent scenarios.

(I'm not for or against yet, I'm just proceeding through the arguments.)
 
  • #66
See, your "held back perhaps by a tensionmeter, no wind" is a question that just doesn't make any sense.

Ok, how come Jack Goodman has done just that and gotten a result?
 
  • #67
LURCH said:
If it can go downwind faster than the wind, then it can sail when there is no wind. After all, that would just be going "faster" than the stationary air around it.

In fact, it must do exactly that at some point during the test run in the video. Somewhere along that run, the craft is stationary relative to the air around it, yet contiues to accelerate. This means that, as stated above, the craft can sail during a dead-calm. This amounts to a sailing craft that needs no energy input to provide propulsion.

In the above, you're confusing "craft" with "sails". Unlike a traditional sailing vessel, the wind seen by the chassis of the craft and the sails of the craft are not the same.

At the moment the *chassis* reaches the speed of the wind, the sails are moving quite nicely through the air.

The above is no different than taking two ice-boats on mirror zig-zag downwind tacks and placing a sliding beam between them -- give me two seats and a windsock right in the middle of the beam between the boats. You and I sit in those seats and watch the windsock. Yep, sure enough ... at the moment we reach the real wind speed, the sock hangs limp. Do the twin ice-boats that we are riding on care? ... of course not -- they are zigging and zagging and see plenty of wind as they accelerate us both to a VMG of greater that 1.0 and the sock turns into our face.

See, the above is nothing at all like stating that our ice-boats can sail in dead-calm. If the wind over the ice stops, the boats stop and we stop. Same with the cart.

JB
 
  • #68
PhysicsAddict said:
In order to understand this you need not understand sailing, relative wind, apparent wind or ANYTHING other than Newtons 1st law.

To get your head around this, imagine the cart facing west sitting on a long treadmill in a long windless hallway. Start the treadmill which runs towards the east and slowly increase the treadmill speed until the cart is at the perfect “break even” point. In other words, to an observer standing still in the hallway, the cart appears to also be standing perfectly still even though it is on the treadmill with its wheels spinning and propeller turning. This is the point where the cart goes EXACTLY as fast as the wind downwind. We don’t need it to go faster than the wind downwind yet. Right here at the break even point is the best place to get your head around it.

Now you don't need to understand anything more that two simple ideas:

1. You must understand Newton’s 1st law of motion - specifically pertaining to balanced and unbalanced forces. In order for the cart to appear to stand perfectly still on the treadmill, the forces pushing on the cart from the east must equal the forces pushing on the cart from the west.

In other words, let’s say that the treadmill is expending 10 Newtons of energy driving the cart east. Since the forces are balanced, the propeller on the cart must be expending 10 Newtons of energy driving the cart west in order to hold it stationary. Since the cart is not experiencing ANY wind pushing it at this point, all its energy driving it west must come from thrust generated by the propeller.

2. You must understand that mankind has yet to invent a machine simple or complex that outputs 100% of the energy it consumes. A propeller is at best 85% efficient. Add in the other components of friction and well it all goes downhill from there. In other words it would be impossible for the cart even get to this break even point. It will never generate thrust equal to the energy it consumes. Now to go even faster than the wind it will have to generate thrust IN EXCESS of the energy it consumes which of course is never going to happen.

Since you now understand these two simple ideas, you can now conclude that the video can only be either:

A. A hoax.
B. Some other "artifact" captured on film.

So here it is reduced to it's minimum components. Nothing to obfuscate here. Very simple.

If you contend that it is possible then all you need to answer is this simple non-obfuscated problem:

Let's suppose that the treadmill imparts a continuous 10 Newtons of force where the treadmill belt strikes the wheels. Please lay out the equations for me assuming your propeller is 90% efficient (that would be an awesome propeller BTW) and there is no friction in the inner gearing of the device. Show me where the device is able to generate continuous thrust in excess of 10 Newtons in order to break even and stand still.

It's a simple equation I assure you. If you need the equation I can point you toward it.

So if you would please lay it out for us where 10N into the propeller results in >= 10N of thrust out.
Hm. Can't find a flaw in this argument. It does seem to eliminate all the confusing components, leaving nothing but an over-unity paradox, wherein the wheels must drive the propellor to generate more thrust than the wheels are getting from the treadmill.
 
  • #69
Trond said:
Ok, how come Jack Goodman has done just that and gotten a result?

He hasn't -- you're simply continue to misunderstand what he's done. I can say this with certainty as to me he's merely a phone call away.

This device WILL NOT work when there is no wind relative to the ground.

JB
 
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  • #70
It will never generate thrust equal to the energy it consumes.

It doesn't have to, going down wind it needs less energy at same speed, just like an airplane going down wind, or you can obtain a higher speed then upwind. All relative the ground of course. Same speed relative the air. And I'm never talking relative the rotating blades. Always cart.
 
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