How can I use the formula k=4pi^2m/T^2 to find the mass of a bolt?

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To find the mass of a bolt using the formula k=4π²m/T², it is crucial to isolate k correctly, which has been done as k=4π²/T². The discussion emphasizes the importance of using multiple pairs of measurements to accurately determine k, rather than relying on a single set of values. By plotting the corresponding values in a linear regression format, the slope can provide a more accurate estimate of k. This method allows for better analysis and understanding of the relationship between mass and period. Overall, using multiple data points and regression analysis is essential for accurate calculations.
Chely
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Homework Statement
Use your data to calculate the spring constant, k, of the spring. (Hint: What variables do you need to plot in order to produce a linear graph in order to calculate k?)
Relevant Equations
T^2=\frac{{4\pi}^2}{\kappa}m,\ which\ can\ be\ compared\ to\ y=mx+c
k=\frac{{4\pi}^2m}{T^2}\Longrightarrow=\frac{{4\pi}^2.05}{{\mathbf{0}.\mathbf{965}}^2}
I managed to isolate k to k=4pi^2/T^2 however I don't know If I did it correctly. I am trying to use K to find the mass of a bolt. I am stuck here, not sure If i need to find all three k's and then average them out?
 

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Chely said:
##T^2=\frac{{4\pi}^2}{\kappa}m##
which can be compared to ## y=mx+c##
##k=\frac{{4\pi}^2m}{T^2}\Longrightarrow=\frac{{4\pi}^2.05}{{\mathbf{0}.\mathbf{965}}^2}##

I managed to isolate k to ##k=4\pi^2/T^2 ## however I don't know If I did it correctly. I am trying to use K to find the mass of a bolt. I am stuck here, not sure If i need to find all three k's and then average them out?

I assume you mean ##k=4\pi^2m/T^2 ##. But then you used that with just one pair of values. The idea of having it in the form y=mx+c is to decide what x and y correspond to in your measurements then plot y against x and use linear regression to find the best fit. The slope then gives you information about k.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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