- #1
Alfredomaximun
- 2
- 0
Thread moved from the technical forums to the schoolwork forums
Summary: ##M=3\left(n-1\right)-2j_1-j_2##
Hi, I'm trying to get the degrees of freedom of a can crusher.
So substituting I get
##
\begin{array}{l}M=3\left(n-1\right)-2j_1-j_2\\
n=5\\
j_1=5\\
M=3\left(5-1\right)-2\cdot 5-0\\
M=2\end{array}
##
And I would think it would be 1
Hi, I'm trying to get the degrees of freedom of a can crusher.
So substituting I get
##
\begin{array}{l}M=3\left(n-1\right)-2j_1-j_2\\
n=5\\
j_1=5\\
M=3\left(5-1\right)-2\cdot 5-0\\
M=2\end{array}
##
And I would think it would be 1