How Do Forces and Motion Affect a Baseball When Hit by a Bat?

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The discussion centers on the physics of a baseball being hit by a bat, focusing on the forces and resulting motion. The bat exerts an average force of 500N on the baseball, which is 0.15 kg, for 0.20 seconds. The force applied by the baseball on the bat is equal and opposite, also 500N. The calculated acceleration of the baseball is 3333.3 m/s², leading to questions about the resulting speed after the impact. Concerns are raised about the validity of the force and time interval, suggesting that the resulting velocity may be unrealistically high.
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Homework Statement


As a baseball player strikes the ball with his bat, the 1-kg bat applies an avg force of 500N on the 0.15 kg baseball for 0.20seconds.

a. What is the force applied by the baseball on the bat?
b. What is the acceleration of the baseball?
c. What is the speed of the baseball at the end of the 0.2 seconds?

Homework Equations


The Attempt at a Solution


a.) 500N
b.)3333.3
c.) NO CLUE
 
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MoreZitiPlease said:

Homework Statement


As a baseball player strikes the ball with his bat, the 1-kg bat applies an avg force of 500N on the 0.15 kg baseball for 0.20seconds.

a. What is the force applied by the baseball on the bat?
b. What is the acceleration of the baseball?
c. What is the speed of the baseball at the end of the 0.2 seconds?

The Attempt at a Solution


a.) 500N
b.)3333.3 m/(sec^2)
c.) NO CLUE

Aw, now I bet you have at least a little clue... I added the units for acceleration to your answer for part (b). Now if the ball is taken to be starting from rest at the start of the bat's impact, and the ball is being accelerated (on average) at 3333.3 m/(sec^2) for 0.2 second, how fast would it be going at the end of that interval? (How do you figure velocity from acceleration?)

[I'm not sure I believe the 500 N for the average force or the impact interval of a whole 0.2 second: the resulting velocity is really excessively large. But if that's what the problem says...]
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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