How Do Suspended Charged Spheres Behave?

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The discussion focuses on the behavior of two charged spheres suspended from a common point, addressing their electrostatic interaction when given the same charge. It explains that the electrostatic force acting on the spheres equals the gravitational force component, expressed as mgtan(theta). The approximation of tan(theta) as d/2L is justified for small angles, with a noted percent error if d is L/10. The conversation culminates in deriving the relationship for charge using Coulomb's law, leading to the formula abs(q) = sqrt((mgd^3)/(2kL)). The thread highlights the interplay between electrostatics and geometry in analyzing the system.
Nevok
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Homework Statement


This is a long one...
Two small spheres with mass m are suspended with insulating threads of length L from a common point. Uncharged, the spheres hang so they touch each other. When given the same charge q they repel each other and hang d distance apart. Assume d is pretty small when compared to L but not the the diameter of the spheres.

a) Explain, using a net force diagram, why the magnitude of the electrostatic force F_e acting on the spheres must be equal to mgtan(theta)

b) Explain why in this situation we can approximate tan(theta) as d/2L and what the percent error if d=L/10

c)Combine the answers to part a and b with Coulombs law to show that abs(q)= sqrt((mgd^3)/(2kL))
L=70cm, d=4.0cm m=0.4g

Homework Equations


Coulombs law, F_e=(k(q_1*q_2))/r^2.

The Attempt at a Solution


Well, I have part a, but i have no clue about why you could do that approximation.
 
Last edited:
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Hello nevok. For really small angles, \sin \theta \approx \tan \theta
 
Thanks, with that and a little bit of thinking I solved it.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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