How Do You Calculate Frictional Force on a Block?

AI Thread Summary
To calculate the frictional force on a 10-lb block subjected to a 3-lb horizontal force, the static friction coefficient (\mus) is 0.5 and the kinetic friction coefficient (\muk) is 0.4. The maximum static friction force required to move the block is calculated to be approximately 49.0 lb, or 22N. Since the applied force of 3-lb (about 1.4N) is less than this maximum, the frictional force equals the applied force. Thus, the frictional force acting on the block is 3-lb.
mdawg467
Messages
14
Reaction score
0

Homework Statement


A 3-lb horizontal force is applied to a 10-lb block on a rough horizontal surface. The block is initially at rest. If \mus is 0.5 and the \muk is 0.4, the frictional force on the block is?


Homework Equations


FN=mg
Fk=\mukFN
Fs,max=\musFN


The Attempt at a Solution


I found \mus,max required to move the 10-lb block was 49.0 lb/ms^2..or approximately 22N.

Since the force being applied is 3-lb, or approximately 1.4N, then the frictional force must be equal to the force being applied correct?

Thanks.
 
Physics news on Phys.org
mdawg467 said:

Homework Statement


A 3-lb horizontal force is applied to a 10-lb block on a rough horizontal surface. The block is initially at rest. If \mus is 0.5 and the \muk is 0.4, the frictional force on the block is?


Homework Equations


FN=mg
Fk=\mukFN
Fs,max=\musFN


The Attempt at a Solution


I found \mus,max required to move the 10-lb block was 49.0 lb/ms^2..or approximately 22N.

Since the force being applied is 3-lb, or approximately 1.4N, then the frictional force must be equal to the force being applied correct?

Thanks.

Sounds good - especially in America where apparently the pound is a unit of Force, not a unit of mass.
 
Thank you!
Yeah only here in America haha..
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Back
Top