How Do You Calculate Half-Life from an Exponential Decay Equation?

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To calculate half-life from the exponential decay equation Y=Ae^(-t/λ), the half-life can be expressed as t(1/2) = ln(2)/λ. The discussion highlights the challenge of incorporating the initial amount A into the half-life equation. By manipulating the equation A/Ao = e^(-λt), one can derive a relationship for λ. Ultimately, the half-life can be expressed as t(1/2) = ln(A/Ao)/λ, maintaining the dependence on both A and λ. This provides a comprehensive understanding of how to relate half-life to the initial amount and decay constant.
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Homework Statement


Given Y=Ae-t/(lambda) find the half life in terms of A and lambda

Homework Equations



Y=Ae-t/(lambda)

The Attempt at a Solution


every time t is a multiple of lambda the relationship then becomes (lambda(n)=A/e^n), i can't figure out how that will relate, i also tried setting the equation to A/2 however that just canceled out the A. Need help!
I figured it out t(1/2)=ln(2)/lambda, however i don't know how to incorporate A into this
 
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Expression of radioactive is written as
A = Ao*e^-λt...(1)
As you have mentioned
t_1/2 = ln(2)/λ.
The equation (1) can be written as
A/Ao = e^-λt. or
Ao/A = e^λt
Take logarithm of both the side and fine the expression for λ. Put it in the t_1/2 equation.
 
rl.bhat if i put the expression into lambda in the t_1/2 equation then i lose the lambda, i need to express it in lambda and A
 
In that case
t_1/2 = ln(A/Ao)/λ
 
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