How Does Air Resistance Affect Work Done on a Falling Raindrop?

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A raindrop with a mass of 3.51 x 10^5 kg falls at a constant speed due to the balance between gravitational force and air resistance. The acceleration due to gravity is 9.8 m/s^2, and after falling 115 m, the work done by air resistance is equal in magnitude to the work done by gravity. Since the forces are balanced, the net force is zero, indicating that air resistance counteracts gravity. The work done by air resistance can be calculated as the force multiplied by the distance fallen. This illustrates the relationship between force, distance, and work in the context of falling objects.
the_d
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A 3.51 x 10^5 kg raindrop falls vertically at
constant speed under the influence of gravity
and air resistance.
The acceleration of gravity is 9.8 m/s^2 :
After the drop has fallen 115 m, what is the
work done by air resistance?

would it be opposite of that done by gravity which i found to be 3.955 x 10^-2?
 
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the_d said:
A 3.51 x 10^5 kg raindrop falls vertically at
constant speed under the influence of gravity
and air resistance.
The acceleration of gravity is 9.8 m/s^2 :
After the drop has fallen 115 m, what is the
work done by air resistance?

would it be opposite of that done by gravity which i found to be 3.955 x 10^-2?
CORRECT.


~~~
 
Last edited:
Yes,"constant speed" means that the 2 forces are perfectly balanced.Since they act on the same distance,u could say the the workd done by gravity is equal in modulus with the one done by friction force.

Daniel.
 
Exactly.

Since the raindrop is falling at constant speed, the net force on it is 0. That means that the air resistance force is equal to but opposite the force of gravity. The work done is just that force times the 115 m distance.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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