How Does an Antiproton Accelerate in Combined Electric and Magnetic Fields?

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An antiproton with a velocity of 500 m/s is subjected to a magnetic field of 2.5 T and an electric field of 1000 V/m. The relevant equations include F=ma and F=qvB, but the presence of the electric field complicates the calculation of acceleration. The correct magnitude of the antiproton's acceleration is determined to be 2.4x10^10 m/s². The discussion highlights confusion regarding the role of the electric field in the acceleration calculation. Understanding the interaction between electric and magnetic forces is crucial for solving such problems.
ursulan
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Homework Statement


An antiproton (same properties as a proton except that q=-e) is moving in the combined electric and magnetic fields of the figure

The antiproton is moving to the right with a velocity of 500m/s the magnetic field B=2.5T is coming into the page and E=1000V/m downward.

What is the magnitude of the antiproton's acceleration at this instant?

Homework Equations



F=ma, F=qvB

The Attempt at a Solution



The answer is 2.4x10^10m/s^2. I bascially went ma=qvB which didn't work. I'm not sure why it shows E.
 
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ursulan said:

Homework Statement


An antiproton (same properties as a proton except that q=-e) is moving in the combined electric and magnetic fields of the figure

The antiproton is moving to the right with a velocity of 500m/s the magnetic field B=2.5T is coming into the page and E=1000V/m downward.

What is the magnitude of the antiproton's acceleration at this instant?

Homework Equations



F=ma, F=qvB

The Attempt at a Solution



The answer is 2.4x10^10m/s^2. I bascially went ma=qvB which didn't work. I'm not sure why it shows E.

Maybe this will help?
http://hyperphysics.phy-astr.gsu.edu/hbase/magnetic/magfor.html#c2
 

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