How Does Changing Plate Distance Affect Interference Patterns in Interferometry?

  • Thread starter Thread starter binbagsss
  • Start date Start date
  • Tags Tags
    Interference
AI Thread Summary
Changing the distance between plates in interferometry affects the number of observable rings due to variations in path difference, which is influenced by the wavelength of the light source. When plates are moved closer together, fewer rings are observed because the path difference becomes less conducive to constructive interference, as described by the path difference equation. For non-monochromatic sources like a Sodium Lamp, the D line with the shorter wavelength changes more rapidly, impacting the interference pattern at different rates. Additionally, altering the distance can lead to observable effects such as changes in ring brightness or visibility. Understanding these relationships is crucial for analyzing interference patterns in various optical setups.
binbagsss
Messages
1,291
Reaction score
12
- why is it that fewer rings are observed when the plates are moved closer together (given wavelength , monochromatic source). What equation shows this relation?

- Consider a non-monochromatic source, such as a Sodium Lamp, as the distance varies, both patterns change but at differnt rates - one will change at a faster rate than the other - which one changes quicker - the D line with the greater or smaller wavelength? And why is this, again is there an equation to show this relation?

- As the distance between the plates is changed, the number of rings observed changes also - are there any other observable affects varying with this distance?

Thanks a lot anyone for any assistance !
 
Physics news on Phys.org
also see: your other thread about this interferometer for the context.
binbagsss said:
- why is it that fewer rings are observed when the plates are moved closer together (given wavelength , monochromatic source). What equation shows this relation?

http://hyperphysics.phy-astr.gsu.edu/hbase/phyopt/fabry.html
Take a look at the geometry panel - when the path difference (length CD) is an integer number of wavelengths you get constructive interference and thus a maxima. CD depends on the angle and how far apart the plates are by simple geometry.

To understand this - sketch the diagram with different plate separations.

- Consider a non-monochromatic source, such as a Sodium Lamp, as the distance varies, both patterns change but at differnt rates - one will change at a faster rate than the other - which one changes quicker - the D line with the greater or smaller wavelength? And why is this, again is there an equation to show this relation?
Again, it is the path difference equation ... the path difference needs to be a whole number of wavelengths.
Work it out.

- As the distance between the plates is changed, the number of rings observed changes also - are there any other observable affects varying with this distance?
What sort of effect did you have in mind?
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top