How Does Horizontal Force Balance with Friction on an Inclined Plane?

AI Thread Summary
To analyze the equilibrium of a 2.00 kg block on a 55° incline, the horizontal force F must balance the gravitational and frictional forces acting on the block. The coefficient of static friction is given as µ s = 0.300, which is essential for calculating the frictional force. Starting with a free-body diagram helps in identifying the forces in both the x and y directions, leading to the equations of motion. The net forces in both directions must equal zero, allowing for the determination of the minimum value of F and the normal force exerted by the incline. Understanding these relationships is crucial for solving the problem effectively.
ngorecki
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A 2.00 kg block is held in equilibrium on an incline of angle θ = 55° by a horizontal force, F. If the coefficient of static friction between block and incline is µ s = 0.300, determine
(a) the minimum value of F and
(b) the normal force of the incline on the block.

F = ma
Mu = Ff/Fn

I am having trouble starting out. I don't know what the initial equation should be. Could i get some hints?
 
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Always, always, always start with a free-body diagram. Have you done that yet?
 
I have done that.
And i changed gravity into the x and y components.
I am not sure what to solve for first/how to solve for it
 
The object is in equilibrium, so the net force in the x direction equals zero and the net force in the y direction equals 0. Now solve for that force F in the x and y direction to find its components.
 

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