How Far Does a Car Travel Accelerating Uniformly from Rest to 20 m/s West?

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A car accelerates uniformly from rest to a velocity of 20 m/s west with an acceleration of 2.50 m/s². The time taken to reach this velocity is calculated to be 3.2 seconds. Using the displacement formula, the total displacement during this time is found to be 32 meters west. The calculations are confirmed to be correct. This demonstrates the relationship between acceleration, time, and displacement in uniform motion.
kselanders
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Homework Statement



A car accelerates uniformly from rest. If the acceleration was 2.50 m/s^2 west, what was its displacement when it reached a velocity of 20.0 m/s west?

Homework Equations


The Attempt at a Solution



A= 2.50 m/s^2 west
Vi= 0 m/s
Vf= 20 m/s west

vf=vi+at
20m/s=2.50m/s^2(t)
20m/s/2.50m/s^2=t
t=3.2sxf=xi+1/2(vf+vi)t
xf=1/2(20m/s)(3.2s)
xf=(10m/s)(3.2s)
xf=32m
 
Last edited:
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Hi kselanders, welcome to PF.
vf=vi+at
20m/s=2.50m/s^2(t)
20m/s/2.50m/s^2=t
t=3.2s

Check this calculation.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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