How Far Must a Small Piston Be Pushed to Lift a Larger One by 20 cm?

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To determine how far a small piston must be pushed to lift a larger piston by 20 cm, the principle of hydraulic systems is applied, which states that the volume displaced by the small piston equals the volume displaced by the larger piston. The equation used involves the relationship between the diameters and the distances moved by the pistons, considering the incompressibility of the liquid. The relevant equations include those related to pressure and volume, specifically focusing on the area of the pistons and the distances they move. The calculations will yield the necessary distance the smaller piston must be pushed down. Understanding these principles is crucial for solving hydraulic lift problems effectively.
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1. How far must a 2.0-cm-diameter piston be pushed down into one cylinder of a hydraulic lift to raise an 8.0-cm-diameter piston by 20 cm?



Homework Equations





3. what equations do i use is it pV=nRT
 
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Volume displaced by small piston must be equal to volume displaced in bigger cylinder. The liquid is taken to be incompressible.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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