How far must the quarterback throw the ball?

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The discussion focuses on calculating the distance and direction a quarterback must throw the ball based on the receiver's movements and the quarterback's position. The receiver's final coordinates are determined to be (17, 27), while the quarterback is at (0, -7). The distance is calculated using the Pythagorean theorem, resulting in approximately 38.0 yards. The angle of the throw is found to be 26.5 degrees to the right of downfield. The calculations confirm the required throw distance and direction.
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Homework Statement



At Enormous State University (ESU), the football team records its plays using vector displacements, with the origin taken to be the position of the ball before the play starts. In a certain pass play, the receiver starts at +2.0 {i} - 5.0 {j}, where the units are yards, {i} is to the right, and {j} is downfield. Subsequent displacements of the receiver are +9.0 {i}(in motion before the snap), +10 {j}(breaks downfield), - 6.0{i}+ 4.0 {j}(zigs), and +12.0{i} + 18.0 {j} (zags). Meanwhile, the quarterback has dropped straight back to a position - 7.0 {j}.How far must the quarterback throw the ball?


In which direction must the quarterback throw the ball?

Homework Equations



Probably Rx+Ry=R

The Attempt at a Solution



I drew the diagram.

Do I have to use two triangles to figure this out, then add those vectors, or something? I would find the components but I don't have any angles to work with(that I know of).

Did you guys have the receiver end on coords (17,27) and the QB on coords(0,-7)?

(17)^2+(34)^2, then square root = 38.0 yards
tan-1 (34/17) = 90-63.43 = 26.5 degrees to right of downfield.

Is that right for yards. Doesn't seem right.
Thanks!
 
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What's the question?
 


How far must the quarterback throw the ball?In which direction must the quarterback throw the ball?
 


Alright, I figure out this is correct.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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