How long did this car accelerate

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A user seeks assistance with a physics problem involving a car that accelerates at 2.4 m/s² until it reaches a speed of 16 m/s. The key equations discussed include v = u + at for calculating time and ax = ½v² for determining distance. There is some confusion regarding the initial velocity, which can be assumed to be zero for this problem. Additionally, the user inquires about calculating the total charge of a paint particle carrying 1.2 x 10^10 electrons, confirming the charge of one electron as -1.6 x 10^-19 coulombs. The discussion emphasizes the importance of showing work and understanding the underlying physics concepts.
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Hello

I need help with a question i am doing: A car accelerates at 2.4ms^-2 until it reaches a speed of 16ms^-1 how long did it accelerate for? and what distance did it travel while accelerating? could someone please help me...
Thanks
Ryan
 
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Use Newton's laws and show ur work.(forum rule : Show people the path, don't drive them through).
 
um yeah that's where its gets difficult cuause i don't know how.. I am not very good at physics... mayb u could show me a couple more tips...a few formulas or something
thanx
 
k. one of the equation is v = u + at
where v - final vel.
u - initial vel.
a - acceleration
t - time
since its not clear(atleast to me) what is the initial vel. you can take it to be zero or report the question is wrong :)
 
ok thank u a lot for your help i also have another question:

the charge of one electron is -1.6x10^-19 am i correct?

so if i have a paint particle that carries 1.2 x 10^10 electrons (12000000000)what is the toatal charge it carries: i tried -1.6x10^-19 = -0.00000000000000000016 so i tried
-0.00000000000000000016 x 12000000000 electrons is this method correct? thanks again
 
ryansmith885 said:
Hello

I need help with a question i am doing: A car accelerates at 2.4ms^-2 until it reaches a speed of 16ms^-1 how long did it accelerate for? and what distance did it travel while accelerating? could someone please help me...
Thanks
Ryan

To find the time:

v=at

To find the distance:

ax=½v²
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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