How Much Charge Passes Through the Lamp in 1 Minute?

In summary: Applying Kirchoff's current law to the lamp's circuit will result in an incorrect answer because the lamp is not a resistor and the ammeter is not a powered load. Thanks.Putting an ammeter in parallel with a lamp as shown in the second image isn't recommended. Applying Kirchoff's current law to the lamp's circuit will result in an incorrect answer because the lamp is not a resistor and the ammeter is not a powered load. Thanks.
  • #1
Kofyebs
12
2

Homework Statement


Ammeter shows 1.2 A and 1.0 A. How large amount of charge passing through the lamp in 1 minute?
https://physicsforums-bernhardtmediall.netdna-ssl.com/data/attachments/84/84982-6e293679b3592fb475f0f9cac697526f.jpg

Homework Equations


Q=I*t[/B]

The Attempt at a Solution


I = 1.2 + 1.0 = 2.2
t = 1 * 60 = 60
Q = I*t

= 2.2 * 60 = 183 C[/B]
 

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  • #2
Are you sure the current through the lamp is 2.2A?
 
  • #3
cnh1995 said:
Are you sure the current through the lamp is 2.2A?
That's why I'm here for help.
 
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  • #4
Kofyebs said:
That's why I'm here for help.
Why do you think the meters show different currents?
 
  • #5
cnh1995 said:
Why do you think the meters show different currents?
Cuz they have different currents.
 
  • #6
Kofyebs said:
Cuz they have different currents.
One meter shows 1.2A and other shows 1A. Where does the remaining current go?
 
  • #7
cnh1995 said:
One meter shows 1.2A and other shows 1A. Where does the remaining current go?
I don't know. That's the question I got from my teacher. that's why I'm here for solutions.
 
  • #8
Kofyebs said:
I don't know. That's the question I got from my teacher. that's why I'm here for solutions.
Well, providing direct answers is against the rules here. Helpers will only provide hints. Where do you think the current splits? Which meter will show 1.2A and which one will show 1A? Think on these and previous questions.
 
  • #9
cnh1995 said:
Well, providing direct answers is against the rules here. Helpers will only provide hints. Where do you think the current splits? Which meter will show 1.2A and which one will show 1A? Think on these and previous questions.
I am here to find out if my equation is correct.
 
  • #10
I am sure you have been taught Kirchoff's Current Law and how to apply it in problems. What do you get if you apply this law at the middle point at the right side of the circuit?
 
  • #11
Kofyebs said:
I am here to find out if my equation is correct.
Q=I*t is always true.
Kofyebs said:
I = 1.2 + 1.0 = 2.2
t = 1 * 60 = 60
Q = I*t

= 2.2 * 60 = 183 C
This is not correct.
 
  • #12
cnh1995 said:
Q=I*t is always true.

This is not correct.
Thanks
 
  • #13
On my tablet computer i can only view one of the images in the original post but...Putting an ammeter in parallel with a lamp as shown in the second image isn't recommended.
 

FAQ: How Much Charge Passes Through the Lamp in 1 Minute?

What does the equation I=Q/t represent?

The equation I=Q/t represents the relationship between electric current, charge, and time. It states that the current (I) flowing through a conductor is equal to the amount of charge (Q) passing through the conductor divided by the time (t) it takes for the charge to pass.

What are the units for each variable in the equation?

The variable I represents current and is measured in Amperes (A). The variable Q represents charge and is measured in Coulombs (C). The variable t represents time and is measured in seconds (s).

How is the equation I=Q/t used in practical applications?

The equation I=Q/t is used to calculate the amount of current flowing through a circuit or conductor. This is important in designing and maintaining electrical systems, as well as understanding the relationship between voltage, resistance, and current in circuits.

Can this equation be used for both direct current (DC) and alternating current (AC) circuits?

Yes, this equation can be used for both DC and AC circuits. However, it is important to note that in AC circuits, the value of current can vary over time, so the equation is typically used to calculate the average current over a specific period of time.

How does the equation I=Q/t relate to Ohm's Law?

The equation I=Q/t is closely related to Ohm's Law, which states that the current (I) flowing through a conductor is directly proportional to the voltage (V) applied and inversely proportional to the resistance (R) of the conductor. This relationship can be expressed as I=V/R, and when rearranged, it can be seen that I=Q/t is a simplified version of Ohm's Law, where the voltage and resistance are held constant.

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