How Much Gravitational Force Acts Between an Astronaut and a Space Shuttle?

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The gravitational force between a 61 kg astronaut and a 71,000 kg space shuttle, when 81 m apart, is calculated using the formula F = [G(Mm)/r^2]. Initial calculations yielded 48.4 nN, but this was based on an incorrect distance of 84 m. Correcting the distance to 81 m results in a force of approximately 4.40 nN. The discussion emphasizes the importance of using the correct distance in gravitational force calculations. Accurate arithmetic is crucial for obtaining the correct answer.
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Homework Statement


What is the approximate value of the gravitational force between a 61 kg astronaut and a 71000 kg space shuttle when they're 81 m apart?

Homework Equations


F = [G(Mm)/r^2]


The Attempt at a Solution


F = (6.67×10−11 N·m2/kg2)(61 kg)(71,000 kg)÷
(84 m)2 = 48.4 nN.

Web assign marked it wrong?
Is it wrong?
 
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Check your arithmetic, given your set up (which is correct) I get 40.9 nN.
 
shallgren said:
Check your arithmetic, given your set up (which is correct) I get 40.9 nN.

^ That is wrong.
 
Whoops, I just checked what you had filled in the equation as. The problem you wrote says that the shuttle and the astronaut are 81 m apart, but the set-up shows 84 m. My bad.

Using 81 m as the distance, I get 4.40 nN. Unless, of course, the problem actually is 84.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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