How much time do I have to catch a coin?

AI Thread Summary
The discussion centers on the confusion regarding the initial velocity of a coin in relation to different frames of reference. One participant believes the coin's initial velocity is zero, while the other argues it has a velocity in the direction of the walkway. They clarify that acceleration and time are consistent across both frames, but the distance traveled by the coin differs. Ultimately, it is concluded that in Philipp's frame, the total distance the coin must travel includes both the distance due to acceleration and the distance due to its initial velocity. This resolution aligns the equations from both perspectives.
Lotto
Messages
251
Reaction score
16
Homework Statement
When riding up the inclined moving walkway of inclination ##α## and length ##l## a coin drops out of Philipp’s pocket when he is exactly in the middle of it. It falls into one of the grooves on the walkway and starts rolling down without slipping. How much time does Philipp have to catch the coin before it falls under the bottom edge of the walkway? The velocity of the moving walkway is ##v##.
Relevant Equations
I would use an euqation for a rotational kinetic energy ##\frac 12 I{\omega}^2## and an equation for a transfer kinetic energy ##\frac 12 mv^2##. ##I=\frac 12 mR^2##.
I am a bit confused with velocities in this problem. From Philipp's view, the coin's initial velocity is zero, so its transfer kinetic energy is also zero. When I am standing on a non-moving ground, is the coin's initial velocity ##v## in direction the walkway is moving? But won't I get then different times?

From Philipp's view: ##\frac 12 l=\frac 12 at^2##
From my view: ##\frac12 l=\frac 12 at^2-vt##

Where do I do a mistake?
 
Physics news on Phys.org
There are four quantities there. You've assumed correctly that ##a## and ##t## are the same in both frames. And, that ##v## is different in the two frames (##v = 0## in Philipp's frame). What about ##l##? Is that the same in both frames?
 
PeroK said:
There are four quantities there. You've assumed correctly that ##a## and ##t## are the same in both frames. And, that ##v## is different in the two frames (##v = 0## in Philipp's frame). What about ##l##? Is that the same in both frames?
Now I understand, in Philipp's frame, the total way the coin must travel is ##\frac 12 l+vt##, so then the equations are equivalent.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'A bead-mass oscillatory system problem'
I can't figure out how to find the velocity of the particle at 37 degrees. Basically the bead moves with velocity towards right let's call it v1. The particle moves with some velocity v2. In frame of the bead, the particle is performing circular motion. So v of particle wrt bead would be perpendicular to the string. But how would I find the velocity of particle in ground frame? I tried using vectors to figure it out and the angle is coming out to be extremely long. One equation is by work...
Back
Top