- #1
Jake357
- 9
- 2
- Homework Statement
- An electron, having the initial velocity of 10^6 m/s, is approaching from a long distance another electron, which is free and at rest. Calculate the maximum force of interaction between the particles. The answer must be 2.26*10^-10 N
- Relevant Equations
- KE=mv^2/2
F=ke^2/d^2
I tried to make the kinetic energy of the first electron equal to the electric potential work.
mv^2/2=ke^2/d
We have to solve for the minimum distance between them: d=2ke^2/mv^2=5.05*10^-10 m
The force is: F=ke^2/d^2=9*10^-10 N, which is not correct.
mv^2/2=ke^2/d
We have to solve for the minimum distance between them: d=2ke^2/mv^2=5.05*10^-10 m
The force is: F=ke^2/d^2=9*10^-10 N, which is not correct.