How to Solve a Timing Diagram with Multiple Logic Gates?

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The discussion revolves around solving a timing diagram involving multiple logic gates, specifically NAND gates, under various input conditions. The initial conditions provided are combinations of binary values for X, Y, and Z. The calculations for outputs W and V show that both equal 1 under certain conditions. The confusion arises in determining the values for Q and Q', as the outputs depend on the state of the NAND gates and the order of evaluation. The conversation emphasizes the need to analyze the transitions of Q and Q' based on different combinations of V and W to identify stable outputs versus cycles.
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Homework Statement


Draw the diagram for the following circuit given the following conditions:
1) X=Y=Z=1
2)X=Y=1, Z=0
3)X=Y=0, Z=1
4)X=1, Y=Z=0
CircuitPhys.png


Homework Equations



The Attempt at a Solution


[/B]
##W=XZ'+YZ##, ##V=Y'Z+XY##

1) W = 0 + 1 = 1
V = 0 + 1 = 1

and now I'm not sure how to get the values for ##Q## and ##Q'## as for the nand gate:

a|b|out
0|0|1
0|1|1
1|0|1
1|1|0

so it appears as though having one of the inputs to the gate to be true doesn't provide any information without the other one input being known.
 

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Potatochip911 said:
so it appears as though having one of the inputs to the gate to be true doesn't provide any information without the other one input being known.

If we assume that power has been removed for some time prior to providing the inputs, then the NAND gates should be outputting 0 to each other.
 
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Drakkith said:
If we assume that power has been removed for some time prior to providing the inputs, then the NAND gates should be outputting 0 to each other.

Hmm, now I'm confused because depending on whether or not I start at the top or bottom gate outputting 0 I will end up with either ##Q=1##, ##Q'=0## or ##Q=0##, ##Q'=1##
 
I would start by considering the four possible combinations of V and W. For each, consider how the four different states for Q and Q' transition from one to another. Some V, W combinations will produce a stable output for Q and Q', while others will produce cycles.
 
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