Impulse imparted by the ground on the ball?

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The discussion revolves around calculating the impulse imparted by the ground on a ball dropped from a height. The initial calculation provided an impulse of 0.12 kg m/s using the formula impulse = m(vf - vi), with the initial velocity (vi) set to 0 m/s and final velocity (vf) as 1.2 m/s. However, participants noted that the problem also provides information about the ball's rebound height, indicating that the final velocity after the collision should be considered. The confusion arises from the need to accurately determine vf after the collision, factoring in the rebound potential energy. A more thorough approach is necessary to incorporate all relevant data for an accurate impulse calculation.
jevillan
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Homework Statement


A mass 100.0 g is dropped from some height above the ground and rebounds to a point where it has 78% of its initial gravitational potential energy. As it hits the ground, it is moving at 1.2 m/s. What is the impulse imparted by the ground on the ball?


Homework Equations


impulse = m(vf-vi)


The Attempt at a Solution


impulse = (0.1)(1.2 m/s - 0 m/s)
=0.12 kg m/s

I followed the formula for impulse, but i feel like I did it wrong because there was a lot more information given in the problem that I didn't use in my solution
 
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I think you need to take into account the ball's velocity after colliding with the ground.
Also you're saying vf = 1.2m/s but the problem states that vi = 1.2m/s.
To find vf you need to use the information about the gravitational potential energy.
 
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