Incandescent Bulb - suitable approximation for voltage-current curve

AI Thread Summary
When a 2 kW electric kettle and a 60 W incandescent bulb are plugged in series, the kettle's nearly constant resistance aligns with Ohm's law, while the bulb's resistance varies significantly with temperature. The bulb's cold resistance is about ten times lower than its hot resistance, complicating calculations. Despite this, for educational purposes, the exercise remains valid as the kettle's resistance is negligible, and the bulb's voltage remains relatively stable. The resistance of a filament lamp is proportional to its temperature, with significant differences between cold and hot states. Understanding these principles is essential for accurate electrical calculations and teaching.
RodionGork
Messages
6
Reaction score
2
Thread moved from the technical forums to the schoolwork forums
Hi Friends!

Regard the 2 kW electric kettle and 60 W incandescent bulb - what happens if we plug them in series? It is the problem I often ask my students somewhere at the end of the term to check if they remember basic "laws" about electricity. Recently I started collecting some exercises on a web-site, and added this one too - here is the full text - but it is pretty same, the main difference is that now there is precise question to find the power on the kettle in this situation.

This annoys me because calculations are made in assumption both devices behave in concordance with Ohm's law. It is quite close for the kettle (their heating elements made of alloys have almost constant resistance with temperature) - but it is definitely not so with the bulb (whoever tried measuring its resistance in the cold state knows it is about 10 times lower).

It still seems less or more OK for the school exercise, since the kettle will give negligible additional resistance and voltage on a bulb doesn't change much - hence its resistance too. But still I wonder if there exist some popular resistance-temperature approximation for pure metals used in school courses. When I tried to look up the topic in the wiki, I quickly faded out among formulas which seemed quite alien to me - but I understand they aim to be as precise as possible over the whole range of temperatures from zero to thousands.
 
Physics news on Phys.org
The resistance of a filament lamp is proportional to the absolute temperature of the filament. Cold is about 300 K. Hot is about 3000 K. Hence the factor of ten in resistance, and the importance of colour temperature.
The simplest approximation is with two straight lines. R is initially constant until the filament generates IR heat. Once the filament starts to glow, it behaves more like a current regulator. The transmission spectrum of the glass has much to do with the transition from one line to the other.
 
From
https://hypertextbook.com/facts/2004/DeannaStewart.shtml


Screen Shot 2024-08-08 at 2.14.54 PM.png
 
  • Like
Likes Lord Jestocost and Tazerfish
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'A bead-mass oscillatory system problem'
I can't figure out how to find the velocity of the particle at 37 degrees. Basically the bead moves with velocity towards right let's call it v1. The particle moves with some velocity v2. In frame of the bead, the particle is performing circular motion. So v of particle wrt bead would be perpendicular to the string. But how would I find the velocity of particle in ground frame? I tried using vectors to figure it out and the angle is coming out to be extremely long. One equation is by work...
Back
Top