- #141
A. Neumaier
Science Advisor
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Not really. We have measurement results (aka events) only after we specify what in the classical universe is the measurement device and how it is supposed to measure which system of interest. This is external to the Laplacian description of the universe by positions and momenta. Thus measurement theory in a classical universe needs as much externals (i.e., the Heisenberg cut) as measurement theory in a quantum universe.DarMM said:That's the point though. In the classical case we can consider the imprint in the device as some kind of approximation of an event that occurred in the system. This is because all random variables in the classical case can be considered as functions on a space of outcomes. Thus we have some notion of the events of microsystem when no external system is present to register them.
The properties of the underlying probability theory are secondary to that.
This statement is interpretation dependent. For example, it does not hold in the thermal interpretation, where modeling both system and external system is done inside the quantum universe.DarMM said:So quantum theory provides a stochastic description of a system-external system interaction when supplied with a choice of external system, but it is intrinsically incapable of modelling that choice of external system. Moreover this is a feature of any non-Kolmogorovian probability theory.
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