Is My Calculation of Maximum Power Correct in This Circuit Analysis?

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Discussion Overview

The discussion revolves around the calculation of maximum power in a circuit analysis, specifically focusing on the determination of Thevenin equivalent voltage (Vth) and resistance (Rth). Participants explore different methods of analysis, including mesh and nodal analysis, to verify their results.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant proposes that the maximum power can be calculated using the formula Pmax = Vth^2/4Rth and outlines their method for finding Rth by turning off independent sources and using a dependent source.
  • Another participant disagrees with the calculated value of Vth, stating they obtained a different result of 8\frac{4}{7} while agreeing on the value of Rth.
  • There is a question raised about the correctness of the equations used to solve for Vth, prompting further verification from other participants.
  • A later reply confirms the alternative calculation of Vth, leading to a revised understanding of the value being approximately 8.5.

Areas of Agreement / Disagreement

Participants do not agree on the value of Vth, with one participant asserting a different result than the original poster. However, there is agreement on the value of Rth.

Contextual Notes

There are unresolved aspects regarding the correctness of the equations used for Vth, as participants are still verifying their calculations. The discussion reflects differing interpretations of the circuit analysis methods applied.

Who May Find This Useful

This discussion may be useful for students and practitioners involved in circuit analysis, particularly those interested in Thevenin's theorem and maximum power transfer concepts.

salman213
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1. http://img503.imageshack.us/img503/1480/21144697lh1.jpg [/URL]

3.
Pmax = Vth^2/4Rth

so I am guessing i treat R as the Rth and find Rth.

to find Rth i must turn off all independent sources. Since the dependent source exists i added a one voltage source at the Rth terminals and put a current i which i will find. then i can use v=i*Rth to solve for Rth.

my mesh analysis equations:
Vx + 1 =0
-1 + i2 + 2Vx=0

therefore i2 = 3

2i3 + 1 =0
i3 =-1/2



i3 + i1 = i2

therefore

i1 = 1/2 + 3

i1 = 7/2


Rth = (1)/(7/2) = 2/7


now to find Vth

I used nodal analysis and mesh analysis both

1) (12-Vth)/2 = (Vth-2Vx)/1
2) -12 + Vx + Vth=0

Solving I found Vth = 15 V


Pmax = Vth^2/4Rth = (15)^2 / (4(2/7)) = 196.874 W



CAN SOMEONE PLEASE CHECK THAT!


thank you!





 
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I didn't get Vth to be 15V. I got 8\frac{4}{7}. But I got the same value for Rth.
 
are my equations right?

for solving Vth?

1) (12-Vth)/2 = (Vth-2Vx)/1
2) -12 + Vx + Vth=0
 
1) (12-Vth)/2 = (Vth-2Vx)/1
2) -12 + Vx + Vth=0

vx= 12 - vth

(12-Vth)/2 = (Vth-2( 12 - vth))/1

12-Vth = 2Vth-48+4vth

12+48=vth+2vth+4vth
60=7vth

okk ur right its 8.5ishok kool
 

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