- #36
Ich
Science Advisor
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It isn't. It's something to do with positive and negative frequencies going to future null infinity, the latter not cancelling the former as they should in the presence of an event horizon. Or something like that, I didn't understand the derivation.If pair production was used to explain Hawking radiation
HR can't be a process happening exactly at the EH, because the local spacetime at the EH is not different from the spacetime somewhere else.
Of course, if you have a reflector ten times thes mass of the observable universe somehow hovering there, within <<1 attometer from the horizon.How about photons shining at black hole that would due to blueshift in finite, short time get more energy then that of entire observable universe and after sliding near event horizon might come out with same wavelength as the had? Is that possible?
Yes.I think I know now what happens to energy in the case I presented.
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So even if you got rid of your mass by converting it to energy traveling at exact speed of light you still couldn't get significant part of you out.
it's exactly the same with Schwarzschild coordinates. These are supposed to be static coordinates. You'd like to place static observers (with r=const.) everywhere, and the solution blows up and then gets imaginary for r<=2M. So it tells you that there's no solution to the problem, just like in your example.If you have simple problem like this: "You see remote object traveling with constant speed v1 and you yourself have speed v2 then at what direction you should point your speed vector to intercept this object?" You can formulate quadratic equation to solve this problem. If you get delta < 0 than right course is stating that this problem has no solutions not stating that this pathology is just result of using real numbers
Also like in your example, that doesn't mean that spacetime is broken. You just can't place a static observer there. If you allow non-static observers, you can place them everywhere (the singularity remains a problem of course). That's reflected in the presence or absence of coordinate failures in the coordinarte systems that are based on the respective observers.
If you allow for arbitrary v2 in your example, you'll get it fixed the same way.
From your answers to nismaratwork:
I'm usually talking about infalling test particles, which do not affect the horizon. If you'd throw in a significant mass, the EH would expand. But it would do so before the mass actually reaches it, so it still wouldn't cross it.I think that ICH agreed with me on the first line of his post that this does not happen.nismaratwork said:The event horizon probably fluctuates as the BH gains mass from infalling matter,
Contrary to what you can see, there are different diagrams showing different things "actually happening". There are some where there is no horizon at all*, and others, where the horizon cannot be crossed in finite time.I'm not asking about what I can see. I'm interested in what actually happens in there in sense of the diagrams that Ich directed me to.
And what I got from this thread so far is confirmation of my own concerns:
If you are far from event horizon no matter how long you wait no falling object ever passes any event horizon.
*: as far as the specific class of observers is concerned.
The interior of a black hole is defined in a coordinate independent way, so I think you should say that in these coordinate systems, particles "actually" cross the horizon in a finite time.