Kinetic Energy of a Particle in a semi-spherical bowl

[Joshua Lee]

Homework Statement

A 410 g particle in a semi-spherical bowl of radius 0.9 m is released from rest at point A at the level of the center of the bowl, and the surface of the bowl is rough. The speed of the particle at B is 2.6 m/s. The acceleration of gravity is 9.8 m/s 2 . What is its kinetic energy at B? Answer in units of J.

Homework Equations

KE= (1/2)mv^2

The Attempt at a Solution

KE= (1/2)(410)(2.6)^2= 1385.8

 

[mfb]

You should work with units, that would have helped you to spot your mistake here.

 

[Ryan Kayan]

Remember that a joule is equal to 1 N⋅m