Lift required to sustain a refueling jet

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To determine the additional lift required for a refueling jet, the force exerted by the fuel flow must be calculated. The fuel flow rate is 20 kg/s at a velocity of 30 m/s, leading to a force of 600 N. Considering the angle of 30 degrees, the vertical component of this force can be found using the sine function, resulting in an additional lift requirement. The discussion emphasizes the importance of analyzing the problem through momentum and impulse rather than solely relying on basic force calculations. Accurate calculations are crucial for understanding the dynamics of mid-air refueling operations.
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Homework Statement


A jet is refueled in mid-air by a tanker. The fueling boom enters the aircraft at an angle of 30 degrees from its flight path. The fuel flow rate is 20kg/s at a velocity of 30m/s with respect to the two aircrafts. The density of the fuel is 700kg/m^3
What is the additional lift needed to overcome the additional force?


Homework Equations


F= ma

The Attempt at a Solution


As Force is kg m/s^2, wouldn't the force be mass flow x velocity?
Then just do sin 30 to the force to get the y component.
But somehow I think I've got the wrong method...
 
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Think about this in terms of momentum and impulse.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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