How to Prove Diagonals Bisect in a Parallelogram

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To prove that the diagonals of a parallelogram bisect each other, set up a coordinate system with one vertex at (0,0) and one side along the x-axis. Assign coordinates to the vertices: (0,0), (a,0), (b,c), and (a+b,c). Calculate the midpoints of both diagonals formed by these vertices. The midpoints will be equal, demonstrating that the diagonals bisect each other. This geometric property is essential in understanding the characteristics of parallelograms.
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I'm not sure how to go about this problem; I'd love a kick in the right direction.

Prove that the diagonals of a parallelogram bisect each other.
 
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Think of it in this terms: what if they don't? what happens then?
 
Since this is titled "linear algebra question", do this:

Set up a coordinate system so one corner of the parallelogram is at (0,0) and one side along the x-axis. Then another vertex is at (a, 0), a third at (b,c) and the fourth at (a+b,c).

Now find the midpoint of each diagonal.
 
Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

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