Mass doesn not effect speed of dropped objects

[Jimmy]

I understood exactly what you meant, Russ. I just posted for ernest's sake. I get the impression that he's being deliberately difficult.

 

[russ_watters]

I understood exactly what you meant, Russ. I just posted for ernest's sake. I get the impression that he's being deliberately difficult.

I figured you did - I was confirming and amplifying.

 

[mikelepore]

The way I like to say that is:
F=ma
a=F/m
The ratio (F_big / m_big) is equal to the ratio (F_small / m_small).
Both are the same value of "a".

What is F_big and F_small?

I meant, for example, drop two objects near the surface of the earth.

Drop a 10 kg object (the smaller mass) and a 100,000 kg object (the bigger mass).

For each object, express its acceleration by expressing the ratio of the gravitational force that the Earth exerts on the object to the mass of the object.

10 kg object:
a = F_small / m_small = 98 N / 10 kg = 9.8 m/s^2

100,000 kg object:
a = F_big / m_big = 980,000 N / 100,000 kg = 9.8 m/s^2

The two objects experience the same acceleration.

 

[TurtleMeister]

I meant, for example, drop two objects near the surface of the earth.

I understand. Thanks for the clarification. I was thinking of the force between the Earth and only one object. My fault in misunderstanding.