Masses on incline plane and pulley.

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The discussion centers on a physics problem involving a system of three masses connected by pulleys, with one mass moving up and two moving down an incline with friction. The user sets up a force equation to find the system's acceleration, incorporating gravitational forces and friction. After calculating, they find the acceleration to be 3.43 m/s². The user realizes they initially overlooked the parallel force component in their calculations. Ultimately, they confirm their solution is correct and express satisfaction with resolving the issue.
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Homework Statement



A suspended 2.87 kg mass is moving up, a 1.5 kg mass slides down the ramp, a suspended 8.4 kg mass on the left is moving down. There is friction between the block and the ramp. The acceleration of gravity is 9.8 m/s2 . The pulleys are massless and frictionless.

Find the acceleration of the 3 block system.
Here is a diagram

http://img8.yfrog.com/i/capturexki.jpg/


Homework Equations



F=ma
Friction=μN
F parallel: mgsinφ
F perpendicular: mgcosineφ

The Attempt at a Solution



Sumation equation I set up (mass 1= 8.4kg, mass 2=1.5kg, mass 3=2.87kg mt=total mass)

m1g-m2g(sinφ)-friction-m3g=mtg

after the numbers are plugged in:

(8.4)(9.8)-(1.5)(9.8)sin36-(0.14)(1.5)(9.8)cos36-2.87(9.8)=12.77a

acceleration would equal=3.43 m/s2

is this correct?
 
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i think your attempt is exactly what the question required
 
I figured it out...

I was forgetting to add the parallel force to the driving force.

All is well now, thanks!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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