Mechanical Energy Homework: Find E of 0.13 kg Ball at 5.00 m

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To find the mechanical energy of a 0.13 kg ball at 5.00 m above the ground and moving at 20.0 m/s, both kinetic and potential energy must be considered. The kinetic energy (Ek) is calculated using the formula Ek = 1/2mv^2, resulting in 26 J. The potential energy (Ep) is determined using Ep = mass x gravity x height, yielding 6.37 J. The total mechanical energy is the sum of kinetic and potential energy, which equals 32.4 J. Understanding the inclusion of potential energy is crucial for solving similar problems.
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Homework Statement



A 0.13 kg ball moves at a rate of 20.0 m/s at the point where it is 5.00 m above the ground. How much mechanical energy does the ball have with respect to the ground?

Homework Equations



Ek = 1/2mv^2

The Attempt at a Solution



Ek = 1/2mv^2
Ek = 1/2(0.13kg)(20m/s)^2
E = 26 J

The assignment says my answer should be 32.4 J.
Obviously, I am doing something wrong, but I'm not sure how to incorporate the "with respect to the ground" bit into my equations.

Somebody offer me some guidance, please?
 
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I can't comment on WHY this is so.. but apparently.. the answer includes the potential energy of the ball as well

= mass x gravity x height

= .13 * 9.80 * 5m = 6.37J

26 J + 6.37J = 32.4J



Not really helping but I'm not familiar with mechanical energy...
 
Hmm...that is strange...I really don't like the way that the question is worded.

But that did help, thank you.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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