- #316
casualguitar
- 503
- 26
I follow, so yes I can get the pressure drop in both regions. Regarding the big uncertainty about where both vapour and liquid are present - will it not be the case though that this region will be present at every position in the bed i.e. moving from inlet to outlet. So, getting the pressure drop for the all vapour case, and the all liquid case should give us the max and min pressure drop that can occur? The pressure would move from the initial pressure drop when the tank is mostly liquid (the lowest pressure drop), up to the max pressure drop when it is all gas. So is it correct to say the saturated region can be ignored, and we can just consider all gas and all liquid?Chestermiller said:You know where you have vapor and where you have liquid, and you can get the pressure drop for each of these regions using the Ergun equation. The only big uncertainty is the region where vapor and liquid are both present, but this is only 1 tank (according to what you have said previously). So tentatively neglect it.
Also - in the previous Ergun calculation I was able to use the actual length of the bed (about 1.4m). However I am not sure how 'long' each tank is. We know that ##L=n\Delta x##, so knowing the total length, say 1.4m, we could decide a value of delta x and this would give us the value of n. Is it correct to say that the length of a tank 'n' in this model is not constant?