- #421
MrRobotoToo
- 97
- 44
Good points. I would just point out that even in the multiparticle case it would still make sense to draw an analogy with a random walk. In the latter case we would want to calculate ##P\left(x_{1},y_{1},z_{1},x_{2},y_{2},z_{2}\right )##, i.e. the probability of finding the particles at ##\vec{x}_{1}## and ##\vec{x}_{2}## after the initial system preparation. The Feynman diagrams for two particles would have a natural translation into a random walk analysis for two classical particles.stevendaryl said:There is another big difference with diffusion, and that is that diffusion is a matter of some substance spreading out in physical space, while a wave function propagates in configuration space. The difference isn't apparent when you're talking about a single particle, but becomes important when you are talking about multiple particles. For two particles, the wave function is a function of 6 variables: [itex]\psi(x_1, y_1, z_1, x_2, y_2, z_2)[/itex] where [itex](x_1, y_1, z_1)[/itex] refers to the location of the first particle, and [itex](x_2, y_2, z_2)[/itex] refers to the location of the second particle. Because it's a function of configuration space, there is no meaning to "the value of the wave function here". So, in spite of the similarity of form, the Schrodinger equation is nothing like a diffusion equation (at least not diffusion through ordinary 3-space).
Last edited: